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STALIN [3.7K]
3 years ago
8

Find the perimeter.

Mathematics
2 answers:
Inessa [10]3 years ago
6 0

Answer:

Perimeter = 120 inches

Area = 176 inches 2

Step-by-step explanation:

For perimeter, all you have to do is add. For area, you would normally have to multiply, but since the numbers are all squared, all you have to do is add them

Fudgin [204]3 years ago
4 0
You got this focus hard
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Find 2 a for a = 3 1/4<br> 1) 6 1/2<br> 2) 6 1/4<br> 3) 23 1/4<br> 4) 5 1/2
Nataly_w [17]

Answer:

  1)  6 1/2

Step-by-step explanation:

Put 3 1/4 where "a" is and do the arithmetic.

  2(3 1/4) = 2·3 + 2·(1/4) = 6 2/4 = 6 1/2

4 0
3 years ago
Show work and Evaluate 3/4 + 2/5
frez [133]

Answer:

23/20

Step-by-step explanation:

Find the common denominator of the 2 fractions (It's 20):

3/4 + 2/5            

Multiply both numerator and denominator by 5 for the first fraction and multiply by 4 for the second fraction:    

15/20 + 8/20        

Add the fractions together:

23/20

5 0
2 years ago
A watermelon seed is 0.4cm long. How far would a line of 126 stretch?
nikdorinn [45]

Answer:

0.504m

Step-by-step explanation:

First, we would multiply 0.4cm by 126 watermelon seeds to find the length of the line in cm.

0.4*126

= 50.4cm

Therefore, the line of watermelon seeds stretches 50.4cm.

Now, because the question wants us to type the answer in meters, we must convert 50.4cm into meters. We do this by dividing 50.4 by 100 since 100cm makes up 1 meter.

50.4/100

= 0.504m

Therefore, the line of watermelon seeds stretches 0.504m.

I hope this helps!

6 0
3 years ago
Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate
Harman [31]

Answer:

Yes

Step-by-step explanation:

Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.

When both machines work for 20 minutes

Machine A would produce = \frac{20}{4} =5 widget and

Machine B would produce = \frac{20}{5} =4 widgets

So we can say that Machine A would produce more widgets than Machine N at that time.

Answer is Yes

8 0
3 years ago
Draw a fraction that is equivalent to 1/6​
iVinArrow [24]
Some equivalent fractions of 1/6 are:
1/6 = 2/12 = 3/18 = 4/24 = 5/30 = 6/36 = 7/42 = 8/48 = 9/54 = 10/60 = 11/66 = 12/72 = 13/78 = 14/84 = 15/90 = 16/96 = 17/102 = 18/108 = 19/114 = 20/120 = 21/126 = 22/132 = 23/138 = 24/144 = 25/150 = 26/156 = 27/162 = 28/168 = 29/174 = 30/180 = 31/186 = 32/192 = 33/198 = 34/204 = 35/210 = 36/216 = 37/222 = 38/228 = 39/234 = 40/240
7 0
3 years ago
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