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2 years ago

PLEASE HELP, WILL GIVE BRAINLIEST + 100 POINTS

Mathematics

1 answer:

attashe74 [19]2 years ago

3 0

Answer:

part A.equation of an ellipse

part B.equation of a hyperbola

part C.domain of each conic section

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What’s the inverse of the equation

alexgriva [62]

Answer:

change the y with the x and solve for y making it the last one

Step-by-step explanation:

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3 years ago

(sqrt3-sqrt3i)^4

Ludmilka [50]

The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.

<h3>Absolute values of the complex numbers</h3>

The absolute values of the complex numbers are determined as follows;

(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

$|z| = \sqrt{(\sqrt{3} )^2 + (\sqrt{3 }\times1 )^2} } \\\\|z| = \sqrt{6}$

(-1+sqrt3i)^12 = (-1 + √3i)¹²

$|z| = \sqrt{(-1)^2 + (\sqrt{3)^2} } \\\\|z| = \sqrt{4} \\\\|z| = 2$

(sqrt 3-i)^6 = (√3 - i)⁶

$|z| = \sqrt{(\sqrt{3})^2 + (-1)^2 } \\\\|z| = \sqrt{4} \\\\|z| = 2$

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

$|z| = \sqrt{(\sqrt{2} )^2 + (\sqrt{2})^2 } \\\\|z| = 2$

(sqrt2-i)^6 = (√2 - i)⁶

$|z| = \sqrt{(\sqrt{2})^2 + (-1)^2} } \\\\|z| = \sqrt{3}$

Increasing order of the complex numbers;

(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.

Learn more about complex numbers here: brainly.com/question/10662770

#SPJ1

3 0

2 years ago

Plz need help like now plz

nika2105 [10]

T) -7x+10y=20. M) -3x+y=-2 - ,
2(8x-5y)=35(2) -1(x+y)=-6(-)

-7x+10y=20. -3x+y=-2
16x-10y=70. -x-y=6

9x=90. -4x=4
[x=10] [x= -1]

-7(10)+10y=20. -3(-1)+y=-2
-70+10y=20. 3+y=-2
10y=90. [y= -5]
[y=9]

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3 years ago

When to use 22/7 for pi?

MAVERICK [17]

You don't use it usually because teachers usually say use 3.14 as an approximation

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3 years ago

[JMC 2011Q7] Peter Piper picked a peck of pickled peppers. 1 peck= 1/4 bushel and 1 bushel= 1/9 barrel.

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3 years ago