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3 years ago

Use the Pythagorean Theorem to answer the questions.

Mathematics

1 answer:

icang [17]3 years ago

7 0

Answer: a. Yes

Step-by-step explanation:

Let the opposite side =12

Let the adjacent side = 16

Let the hypotenuse side =20

Using the pythagoras theorem

we are going to prove that hypotenus is 20

opp² + adj² ⁼ hyp²

12² + 16² ⁼ hyp²

144 + 256 = hyp²

400 = hyp²

√400 =hyp

20= hyp

Therefore hypotenuse= 20

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Hi, how are you today i want you to answer my questions in math subject please because my teacher wants to done by today and sho

kondor19780726 [428]

Answer: see work below

Step-by-step explanation:

1) 3(2f + 4)

distribute the 3

= 6f + 12

2) 3(4t + 2)

distribute the 3

= 12t + 6

3) 7(6k -2v)

distribute the 7

= 42k - 14v

4) 5(2q - 9)

distribute the 5

= 10q - 45

(im not sure what the red mark is. if it's a negative than my answer would be opposite: -10q + 45)

5) 3(2e + 5t)

distribute the 3

= 6e + 15t

(im not sure what the red mark is. if it's a negative my answer would be opposite: -6e -15t)

6) 4(3r - 5)

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7 0

3 years ago

Read 2 more answers

How many centimeters are there in 1 yard if there are 2.54 centimeters per inch? Show your work and express your answer without

sasho [114]

Answer: 91.44

Step-by-step explanation:

There are 3 feet in a yard, 12 inches in a foot. 2.54 x 12= 30.48

30.48 x 3= 91.44

I hope this helps!

3 0

2 years ago

Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

------

Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

------

Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

------

Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$