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2 years ago

Find the set of values of k for which the equation 3x² - 12x + k >. 0 has no real roots.

Mathematics

1 answer:

anzhelika [568]2 years ago

3 0

Answer:

k > 12

Step-by-step explanation:

If a quadratic equation has no real roots the values of b^2 - 4ac

( for the general form ax^2 + bx + c = 0) is negative,

So we have the inequality:

(-12)^2 - 4*3* k < 0

144 - 12k < 0

12k > 144

k > 12

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Molly owes her brother $300.She works for $10 per hour as a checker at the local grocery store.Molly plans to repay her brother

gavmur [86]

Answer: The expression which represents the condition described is given as $4x=300$

Step-by-step explanation:

Since we have given that

Amount that Molly owes her brother = $300

Let the number of hours she worked as a checker be x

Cost of per hour = $10

Amount she get after doing work for x hours is given by

$10x$

Rate of tax are taken out = 80%

So, amount she left with is given by

$\frac{100-20}{100}\times 10x\\\\=\frac{80}{100}\times 10x\\\\=8x$

So, Molly plans to repay her brother half of what she earns is given by

$\frac{8x}{2}=4x$

According to question,

$4x=300\\\\x=\frac{300}{4}\\\\x=75\ hours$

So, the expression which represents the condition described is given as

$4x=300$

3 0

3 years ago

Read 2 more answers

4 value of 546 210 in words

FrozenT [24]

Five hinder and fourty six and two hundred and ten

3 0

3 years ago

The product of 2 and a number minus 9 is 13

algol13

<h3>The value of the number is equal to 11.</h3>

2x - 9 = 13

Add 9 to both sides.

2x = 22

Divide both sides by 2.

x = 11

5 0

3 years ago

Vince weighs 160 pounds, and his friend Nadir weighs 140 pounds. Nadir calculated that his weight on another planet would be abo

vlabodo [156]

160/140 = x/56
cross multiply
(140)(x) = (160)(56)
140x = 8960
x = 8960/140
x = 64 lbs <== Vince's weight on the other planet

5 0

3 years ago

Read 2 more answers

Can somebody help me, please?

Sveta_85 [38]

Answer:

a. $x=10 \textdegree$

$m\angle L=39\textdegree\\\\m\angle M=51\textdegree\\\\m\angle K=90\textdegree$

Step-by-step explanation:

a. We know that angles in a triangle add up to 180°.

-The right angle triangle in the right triangle has a measure of 90°.

We can therefore equate our angles to 180° and solve for x;

$180=\perp\angle+(2x+19)+(3x+21)\\\\180=90+(2x+19)+(3x+21)\\\\90=5x+40\\\\5x=50\\\\x=10\textdegree$

Hence, the angle measure is x=10°

b. Having calculated the value of x from a above as x=10°, we can substitute to find the measures of the two acute angles:

$m\angle L=(2x+19)\textdegree\\\\=(2\times 10+19)\textdegree\\\\=39\textdegree\\\\m\angle M=(3x+21)\textdegree\\\\=(3\times 10+21)\textdegree\\\\=51\textdegree$

Since, the m∠K is a right angle, it measures 90°

8 0

3 years ago

Find the set of values of k for which the equation 3x² - 12x + k >. 0 has no real roots.​

Find the set of values of k for which the equation 3x² - 12x + k >. 0 has no real roots.