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Gnom [1K]
2 years ago
14

Find the set of values of k for which the equation 3x² - 12x + k >. 0 has no real roots.​

Mathematics
1 answer:
anzhelika [568]2 years ago
3 0

Answer:

k > 12

Step-by-step explanation:

If a quadratic equation has no real roots the values of b^2 - 4ac

( for the general form ax^2 + bx + c = 0) is negative,

So we have the inequality:

(-12)^2  - 4*3* k < 0

144 - 12k < 0

12k > 144

k > 12

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A geologist in South America discovers a
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Answer:

This is a radioactive decay / half-life problem.

Initial amount of C 14 = 100% Present Amount = 57%

k = .0001  (that value should be negative)

Nt = No * e^ (k*t)

You need to solve that equation for "time" (equation attached)

time = natural log (Ending amount / Starting Amount) / k

time = natural log (57% / 100%) / -.0001

time = ln (.57) / -.0001

time = -.56211891815 / -.0001

time = 5,621.2 years    (age of the bird skeleton)

These problems are quite complicated but I think I know this pretty well.

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Step-by-step explanation:

7 0
3 years ago
Who wants brainlist and points
postnew [5]

Answer:

6 times 10^3

Step-by-step explanation:

You multiply 3 and 2 together and 10^7 and 10^-4 together. 3x2 is equal to 6 and 10^7 times 10^-4 is the same as 10^7-4 which is equal to 10^3. Therefore, the answer is 6 times 10^3.

If this has helped please mark as brainliest

3 0
3 years ago
A cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 9 inches. The height of the cone is 18 inc
Elan Coil [88]
\sf Cylinder ~volume = \pi r^2 h \\  \\ v = \pi (4)^2(9) \\  \\ v=\pi (16)(9) \\  \\ v=144 \pi  \\ v=452.16\\  \\  \\ Cone~volume = \frac{1}{3} \pi r^2 h \\  \\ v =  \frac{1}{3} \pi (4)^2 (18) \\  \\ v=96 \pi \\ v=301.44 \\  \\  \\ The~ volume ~of ~a ~cylinder ~is~ 1.5~ times~ more ~than ~the ~volume ~of~a~cone.
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3 years ago
Construct a 99​% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample s
vivado [14]

Using the z-distribution, the 99​% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 99% confidence level, hence\alpha = 0.99, z is the value of Z that has a p-value of \frac{1+0.99}{2} = 0.995, so the critical value is z = 2.575.

The estimate and the sample size are given by:

\pi = 0.36, n = 100.

Then the bounds of the interval are:

  • \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.2364
  • \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 2.575\sqrt{\frac{0.36(0.64)}{100}} = 0.4836

The 99​% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
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