The probability of finding 2 never married
10c2*0.4^2*0.6^8=
the probability of finding 1 never married
10C1*0.4*0.6^9=
the probability of finding 0 never married
10C0*0.6^10=
the answer is all the above answers added together.
think you can do the rest of the calculation by yourself. :)
btw nCr=n!/(n-r)!r!
good luck
A. x=the cost of one lunch. 60.25=5x+3(x-5.25)
b. 60.25=5x+3x-15.75 60.25+15.75=8x-15.75+15.75
76=8x 76/8=8x/8 9.50=x
A lunch is $9.50. If you are not sure, check my answers. Hope this helped.
Answer:
540 m so yaaaaàaaaaaaaaaaaaaaaa
In my work I used t=trains and m=minutes:
30+30= 60m/2t
<span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
Total= 720m/24t
1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30= 4 o' clock
Total= 372m/12t
24t+12t= 36t
The answer is:
36 trains in total</span>
Answer:
a^4 - a^3 + a^2 - 2a - (2)/(a + 1)
