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pashok25 [27]
3 years ago
7

casie made a picture graph to record the points that third grade students scored on a test. Mrs wilson group scored 40 Points in

all There are 11 students in Mrs Wilson group what is one way Mrs wilson group may have scored 40 points
Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0
One way, for example, would be the following:
 40/11 = 3.63
 This handle shows that all students of Mrs. Wilson obtained the same number of points (3.63) to reach 40 points.
 Note: there are many ways for 11 students to earn 40 points by making different combinations of notes.
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8_murik_8 [283]
It is stil half becuase the real probability doesnt change
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3 years ago
Point D is the centroid of Triangle ABC. Find CD and CE.<br> DE = 9
sukhopar [10]

Given:

Point D is the centroid of Triangle ABC and DE = 9.

To find:

The measures of CD and CE.

Solution:

We know that, centroid is the intersection of medians and it divides each median in 2:1.

In triangle ABC, CE is a meaning and centroid D divided CE in 2:1. So,

Let the measures of CD and DE are 2x and x respectively.

DE = 9                (Given)

x=9

Now,

CD=2x

CD=2(9)

CD=18

And,

CE=CD+DE

CE=18+9

CE=27

Therefore, the measure of CD is 18 units and the measure of CE is 27 units.

6 0
3 years ago
Multiply and simplify<br><br><img src="https://tex.z-dn.net/?f=35%20%5Ctimes%20%20%5Cfrac%7B7%7D%7B10%7D%20" id="TexFormula1" ti
Kobotan [32]

We can convert 7/10 to a decimal first.

7/10 = 0.7

Now we can multiply this problem easier.

35 x 0.7 = 24.5

6 0
3 years ago
Some students were asked what kinds of animals they have at home.
Nataly_w [17]

(a) Animals by popularity; Dogs, Cats, Others, Horses.

(b) If 250 students were interviewed, 20 students have other pets.

(c) No, it was incorrect.

Step-by-step explanation:

Step 1; We arrange the different pets in chronological order, from the highest percent to the lowest percent;

1. Dogs - 67%,

2. Cats - 20%

3. Others - 8%,

4. Horses - 1%.

None is not included in this list.

Step 2; If 250 students were interviewed, 8% of those have other pets. So we need to calculate how much 8% of 250 is.

8% of 250 = \frac{8}{100} × 250 = 0.08 × 250 = 20.

So 20 students had other pets.

Step 3; 20% of the interviewed students had cats. If 75 students had cats, we need to equate 20% to the 75 and find out how many students were actually interviewed.

20% × x = 75, 0.2 × x = 75,

x = \frac{75}{0.2} = 375.

So if 375 students were interviewed, 75 students would have cats. So the estimate of 250 students being interviewed is incorrect.

8 0
3 years ago
Which graphs show continuous data?<br><br> Select each correct answer.
love history [14]
C

Due to the fact that it is starting from 0 and moving in a steady pattern
5 0
3 years ago
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