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pashok25 [27]
4 years ago
7

casie made a picture graph to record the points that third grade students scored on a test. Mrs wilson group scored 40 Points in

all There are 11 students in Mrs Wilson group what is one way Mrs wilson group may have scored 40 points
Mathematics
1 answer:
SOVA2 [1]4 years ago
7 0
One way, for example, would be the following:
 40/11 = 3.63
 This handle shows that all students of Mrs. Wilson obtained the same number of points (3.63) to reach 40 points.
 Note: there are many ways for 11 students to earn 40 points by making different combinations of notes.
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PLZ HELP I BEGG U! 100 points
rusak2 [61]

Answer:

Solution given;

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b=2ft

h=2ft

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volume=l*b*h=4.5*2*2=18ft³

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5 0
3 years ago
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Solve y = -7(-13)<br><br> I'm giving 30 points!
VARVARA [1.3K]

y = -7(-13)

=> y = -7 × (-13)

= y = 91

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3 years ago
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a company is offering a job with a salary of $30,000 for the first year and a 5% raise each year after that. if the 5% raise con
Ber [7]
<span>First year is 30,000.
</span><span>Earn 5% raise every year.
</span>Growth factor is 1.05 this sounds a lot like a geometric ratio.

An = A1 × r^(n-1)Sn = A1 × (1 - r^n) / (1-r)<span>n = 40
A1 = 30,000
A40 = $30,000 * 1.05^39 = $201,142.53

S40 = A1 * (1 - 1.05^40) / (1-1.05) which becomes:
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<span>The individual yearly calculations are shown below: </span>

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4 years ago
Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

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Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

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The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

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Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

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