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Pani-rosa [81]
1 year ago
9

Find the first two random numbers (to the fifth digit after the decimal point) using linear congruential generator with a=4, m=1

1 and b=0 and 23 as the seed
Mathematics
1 answer:
yulyashka [42]1 year ago
7 0

the first two random numbers are 4,5.using linear congruential generator with a=4, m=11 and b=0 and 23 as the seed

linear congruential  generator

Xn= an-+b Lm

0d s = 25 , b=6, YM 11, 024

Q O o m) 4, Lu) = 4x2%U)

m= 4x4j = 5 y-5

the numbers are 4, 5.

4.O0000 5.000TO

A linear congruence generator is an algorithm that returns a sequence of pseudorandom numbers computed using discontinuous piecewise linear equations. This method is one of the oldest and best-known pseudorandom number generator algorithms.

The linear congruential generator (LCG) is a pseudorandom number generator (PRNG ) is a class of algorithms. Random number generation plays an important role in many applications, from cryptography to Monte Carlo methods.

Learn more about linear congruential here: brainly.com/question/3168048

#SPJ4

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3.
Vitek1552 [10]
To solve this we are going to use the future value of annuity due formula: FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]
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We know for our problem that P=420 and t=15. To convert the interest rate to decimal form, we are going to divide the rate by 100%: r= \frac{10}{100} =0.1. Since Ruben makes the deposits every 6 months, k=2. The interest is compounded semiannually, so 2 times per year; therefore, k=2.
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FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]
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8 0
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45 is 90% of what number
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