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e-lub [12.9K]
3 years ago
14

In a survey of a community, it was found that 85% of the people like winter season and 65% like summer season. If none of them d

id not like both seasons
i) what percent like both the seasons
​
Mathematics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

50%

Step-by-step explanation:

Let :

Winter = W

Summer = S

P(W) = 0.85

P(S) = 0.65

Recall:

P(W u S) = p(W) + p(S) - p(W n S)

Since, none of them did not like both seasons, P(W u S) = 1

Hence,

1 = 0.85 + 0.65 - p(both)

p(both) = 0.85 + 0.65 - 1

p(both) = 1.50 - 1

p(both) = 0.5

Hence percentage who like both = 0.5 * 100% = 50%

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netineya [11]

Answer:

Step-by-step explanation:

.

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7 0
3 years ago
We roll two fair 6-sided dice, A and B. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Find the probab
Jlenok [28]

Answer:

1) 41.67% probability that dice A is larger than dice B.

2) Given hat the roll resulted in a sum of 5 or less, there is a 20% conditional probability that the two dice were equal.

3) Given that the two dice land on different numbers there is a 26.67% conditional probability that the two dice differed by 2.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have these possible outcomes:

Format(Dice A, Dice B)

(1,1), (1,2), (1,3), (1,4), (1,5),(1,6)

(2,1), (2,2), (2,3), (2,4), (2,5),(2,6)

(3,1), (3,2), (3,3), (3,4), (3,5),(3,6)

(4,1), (4,2), (4,3), (4,4), (4,5),(4,6)

(5,1), (5,2), (5,3), (5,4), (5,5),(5,6)

(6,1), (6,2), (6,3), (6,4), (6,5),(6,6)

There are 36 possible outcomes.

1) Find the probability that dice A is larger than dice B.

Desired outcomes:

(2,1)

(3,1), (3,2)

(4,1), (4,2), (4,3)

(5,1), (5,2), (5,3), (5,4)

(6,1), (6,2), (6,3), (6,4), (6,5)

There are 15 outcomes in which dice A is larger than dice B.

There are 36 total outcomes.

So there is a 15/36 = 0.4167 = 41.67% probability that dice A is larger than dice B.

2) Given that the roll resulted in a sum of 5 or less, find the conditional probability that the two dice were equal.

Desired outcomes:

Sum of 5 or less and equal

(1,1), (2,2)

There are 2 desired outcomes

Total outcomes:

Sum of 5 or less

(1,1), (1,2), (1,3), (1,4)

(2,1), (2,2), (2,3)

(3,1), (3,2)

(4,1)

There are 10 total outcomes.

So given hat the roll resulted in a sum of 5 or less, there is a 2/10 = 20% conditional probability that the two dice were equal.

3) Given that the two dice land on different numbers, find the conditional probability that the two dice differed by 2.

Desired outcomes

Differed by 2

(1,3), (2,4), (3,1), (3,5),(4,2),(4,6), (5,3), (6,4).

There are 8 total outcomes in which the dices differ by 2.

Total outcomes:

There are 30 outcomes in which the two dice land of different numbers.

So given that the two dice land on different numbers there is a 8/30 = 0.2667 = 26.67% conditional probability that the two dice differed by 2.

7 0
3 years ago
A number has the digits 6, 2, 9 to the nearest 100, the number rounds to 600 what is the number
eduard

Answer:

629

Step-by-step explanation:

rounds to 629 as t he closest hundred

4 0
3 years ago
A circular flower bed is 19 m in diameter and has a circular sidewalk around it that is 4 m wide. Find the area of the sidewalk
yaroslaw [1]

Answer:

289 m²

Step-by-step explanation:

First find the area of the flower bed

A=πr²= (3.14)(9.5)² = 283.385

Then get the area of everything including the sidewalk

A=πr²= (3.14)(13.5)² = 572.265

Then subtract and you'll get the area of just the sidewalk

572.265 - 283.385 = 288.88m²

4 0
3 years ago
Read 2 more answers
Two things:
Eduardwww [97]
Number one is -6 and 10
Number two is -55 and 4
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3 years ago
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