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o-na [289]
2 years ago
7

Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. {5,5/3,5/9,5

/27...}
Mathematics
1 answer:
Tanya [424]2 years ago
4 0

The formula for the general term of the given sequence 5, 5/3, 5/9, 5/27 is  a_{n} = \frac{5}{3^{n} }.

According to the given question.

We have a sequence  5, 5/3, 5/9, 5/27.

As, we know that "a sequence is an arrangement of any objects or a set of numbers in a particular order followed by some rule"

If we see the given sequence 5, 5/3, 5/9, 5/27 it is following a pattern in which the nummerator of all the terms are same but the denominator is increasing by by power to 3 like 3^0 = 1, 3^1 = 3, 3^2 = 9 and so on.

Thereofre, the genereal term  a_{n}, of the given sequence is given by

a_{n} = \frac{5}{x^{n} } , where n belong to whole numbers.

Hence, the formula for the general term of the given sequence 5, 5/3, 5/9, 5/27 is  a_{n} = \frac{5}{3^{n} }.

Find about more information about sequence here:

brainly.com/question/12952623

#SPJ4

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Can you help me plz in number 12,13,and 14 find the sum or difference.write your answer in simplest form plz explain good so I u
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Answer:

12. 11/18-1/6=4/9

13. 2/7+2/5=24/35

14. 3/4-3/10=9/20

Step-by-step explanation:

12. 11/18-1/6

11/18-1/6=11/18-(1/6)*(3/3)

11/18-1/6=11/18-(1*3)/(6*3)

11/18-1/6=11/18-3/18

11/18-1/6=(11-3)/18

11/18-1/6=8/18

Dividing the numerator and denominator of the fraction on the right side of the equation by 2:

11/18-1/6=(8/2)/(18/2)

11/18-1/6=4/9


13. 2/7+2/5

2/7+2/5=(2/7)*(5/5)+(2/5)*(7/7)

2/7+2/5=(2*5)/(7*5)+(2*7)/(5*7)

2/7+2/5=10/35+14/35

2/7+2/5=(10+14)/35

2/7+2/5=24/35


14. 3/4-3/10

3/4-3/10=(3/4)*(5/5)-(3/10)*(2/2)

3/4-3/10=(3*5)/(4*5)-(3*2)/(10*2)

3/4-3/10=15/20-6/20

3/4-3/10=(15-6)/20

3/4-3/10=9/20

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