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Alla [95]
3 years ago
8

Help please asap just the answers​

Mathematics
1 answer:
Stella [2.4K]3 years ago
4 0

\underline \bold{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  }

\huge\underline{\sf{\red{Problem:}}}

7.) Detemine the value of \sf{ {3a}^{2}  -b.}

\huge\underline{\sf{\red{Given:}}}

\quad\quad\quad\quad\sf{a = 2}

\quad\quad\quad\quad\sf{b =  - 1}

\quad\quad\quad\quad\sf{c =  - 3}

\huge\underline{\sf{\red{Solution:}}}

\quad\quad\quad\quad\sf{⟶{3a}^{2}  - b}

\quad \quad \quad \quad   \sf{⟶{(3)( 2)}^{2}  -( - 1)}

\quad \quad \quad \quad   \sf{⟶3(4)-( - 1)}

\quad \quad \quad \quad   \sf{⟶12-( - 1)}

\quad \quad \quad \quad   \sf{⟶12 +  1 }

\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}

\huge\underline{\sf{\red{Answer:}}}

\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}

8.) Find the value of \sf{ {a}^{3}  {b}^{3}  - abc.}

\huge\underline{\sf{\red{Solution:}}}

\quad\quad\quad\quad\sf{⟶ {a}^{3}  {b}^{3}  - abc}

\quad\quad\quad\quad\sf{⟶{(2)}^{3}  {( - 1)}^{3}  - (2)( - 1)( - 3)}

\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)}  - ( - 2)( - 3)}

\quad\quad\quad\quad\sf{⟶{( - 8)}  - ( 6)}

\quad\quad\quad\quad ⟶\boxed{\sf{  - 14}}

\huge\underline{\sf{\red{Answer:}}}

\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}

\underline \bold{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  }

#CarryOnLearning

\sf{\red{✍︎ C.Rose❀}}

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<h3>1.</h3>

  \ln\left(\dfrac{a^4}{b^4c^{-2}}\right)=4\ln(a)-(4\ln(b)-2\ln(c))=4\cdot2-4\cdot3+2\cdot5=\boxed{6}

<h3>2.</h3>

  \ln\left(\sqrt{b^{-2}c^4a^2}\right)=\dfrac{1}{2}\left(-2\ln(b)+4\ln(c)+2\ln(a)\right)=\ln(a)-\ln(b)+2\ln(c)\\\\=2-3+2\cdot5=\boxed{9}

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<h3>4.</h3>

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_____

The applicable rules of logarithms are ...

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