1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
eimsori [14]
1 year ago
10

Question in pictures

Mathematics
1 answer:
yan [13]1 year ago
7 0

The derivatives of the functions are listed below:

(a) f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}    

(b) f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }

(c) f'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)²    

(d) f'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)]

(e) f'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶

(f) f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}]

(g) f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) -  \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2}  \cdot x^{-\frac{1}{2} }\right)

(h) f'(x) = cot x + cos (㏑ x) · (1 / x)

<h3>How to find the first derivative of a group of functions</h3>

In this question we must obtain the <em>first</em> derivatives of each expression by applying <em>differentiation</em> rules:

(a) f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}

  1. f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}        Given
  2. f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4\cdot x - \frac{x}{5} + 5 \cdot x^{-1} - \sqrt[11]{2022}      Definition of power
  3. f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}       Derivative of constant and power functions / Derivative of an addition of functions / Result

(b) f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}

  1. f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}              Given
  2. f(x) = (x + 3)^{\frac{1}{3} }\cdot (x + 5)^{\frac{1}{3} }           Definition of power
  3. f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }        Derivative of a product of functions / Derivative of power function / Rule of chain / Result

(c) f(x) = (sin x - cos x) / (x² - 1)

  1. f(x) = (sin x - cos x) / (x² - 1)          Given
  2. f'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)²       Derivative of cosine / Derivative of sine / Derivative of power function / Derivative of a constant / Derivative of a division of functions / Result

(d) f(x) = 5ˣ · ㏒₅ x

  1. f(x) = 5ˣ · ㏒₅ x             Given
  2. f'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)]       Derivative of an exponential function / Derivative of a logarithmic function / Derivative of a product of functions / Result

(e) f(x) = (x⁻⁵ + √3)⁻⁹

  1. f(x) = (x⁻⁵ + √3)⁻⁹          Given
  2. f'(x) = - 9 · (x⁻⁵ + √3)⁻⁸ · (- 5) · x⁻⁶       Rule of chain / Derivative of sum of functions / Derivative of power function / Derivative of constant function
  3. f'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶     Associative and commutative properties / Definition of multiplication / Result

(f) f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}

  1. f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}         Given
  2. f'(x) = 7^{x\cdot\ln x} \cdot \ln 7 \cdot (\ln x + 1) + 7\cdot (x\cdot \ln x)^{6}\cdot (\ln x + 1)         Rule of chain / Derivative of sum of functions / Derivative of multiplication of functions / Derivative of logarithmic functions / Derivative of potential functions
  3. f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}]        Distributive property / Result

(g) f(x) = \arccos^{2} x - \arctan (\sqrt{x})

  1. f(x) = \arccos^{2} x - \arctan (\sqrt{x})        Given
  2. f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) -  \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2}  \cdot x^{-\frac{1}{2} }\right)      Derivative of the subtraction of functions / Derivative of arccosine / Derivative of arctangent / Rule of chain / Derivative of power functions / Result

(h) f(x) = ㏑ (sin x) + sin (㏑ x)

  1. f(x) = ㏑ (sin x) + sin (㏑ x)          Given
  2. f'(x) = (1 / sin x) · cos x + cos (㏑ x) · (1 / x)        Rule of chain / Derivative of sine / Derivative of natural logarithm /Derivative of addition of functions
  3. f'(x) = cot x + cos (㏑ x) · (1 / x)      cot x = cos x / sin x / Result

To learn more on derivatives: brainly.com/question/23847661

#SPJ1

You might be interested in
58:11
navik [9.2K]

Answer:

not sure of the answer cause

7 0
2 years ago
A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)equals72 com
solmaris [256]

Answer:

Part (A)

  • 1. Maximum revenue: $450,000

Part (B)

  • 2. Maximum protit: $192,500
  • 3. Production level: 2,300 television sets
  • 4. Price: $185 per television set

Part (C)

  • 5. Number of sets: 2,260 television sets.
  • 6. Maximum profit: $183,800
  • 7. Price: $187 per television set.

Explanation:

<u>0. Write the monthly cost and​ price-demand equations correctly:</u>

Cost:

      C(x)=72,000+70x

Price-demand:

     

      p(x)=300-\dfrac{x}{20}

Domain:

        0\leq x\leq 6000

<em>1. Part (A) Find the maximum revenue</em>

Revenue = price × quantity

Revenue = R(x)

           R(x)=\bigg(300-\dfrac{x}{20}\bigg)\cdot x

Simplify

      R(x)=300x-\dfrac{x^2}{20}

A local maximum (or minimum) is reached when the first derivative, R'(x), equals 0.

         R'(x)=300-\dfrac{x}{10}

Solve for R'(x)=0

      300-\dfrac{x}{10}=0

       3000-x=0\\\\x=3000

Is this a maximum or a minimum? Since the coefficient of the quadratic term of R(x) is negative, it is a parabola that opens downward, meaning that its vertex is a maximum.

Hence, the maximum revenue is obtained when the production level is 3,000 units.

And it is calculated by subsituting x = 3,000 in the equation for R(x):

  • R(3,000) = 300(3,000) - (3000)² / 20 = $450,000

Hence, the maximum revenue is $450,000

<em>2. Part ​(B) Find the maximum​ profit, the production level that will realize the maximum​ profit, and the price the company should charge for each television set. </em>

i) Profit(x) = Revenue(x) - Cost(x)

  • Profit (x) = R(x) - C(x)

       Profit(x)=300x-\dfrac{x^2}{20}-\big(72,000+70x\big)

       Profit(x)=230x-\dfrac{x^2}{20}-72,000\\\\\\Profit(x)=-\dfrac{x^2}{20}+230x-72,000

ii) Find the first derivative and equal to 0 (it will be a maximum because the quadratic function is a parabola that opens downward)

  • Profit' (x) = -x/10 + 230
  • -x/10 + 230 = 0
  • -x + 2,300 = 0
  • x = 2,300

Thus, the production level that will realize the maximum profit is 2,300 units.

iii) Find the maximum profit.

You must substitute x = 2,300 into the equation for the profit:

  • Profit(2,300) = - (2,300)²/20 + 230(2,300) - 72,000 = 192,500

Hence, the maximum profit is $192,500

iv) Find the price the company should charge for each television set:

Use the price-demand equation:

  • p(x) = 300 - x/20
  • p(2,300) = 300 - 2,300 / 20
  • p(2,300) = 185

Therefore, the company should charge a price os $185 for every television set.

<em>3. ​Part (C) If the government decides to tax the company ​$4 for each set it​ produces, how many sets should the company manufacture each month to maximize its​ profit? What is the maximum​ profit? What should the company charge for each​ set?</em>

i) Now you must subtract the $4  tax for each television set, this is 4x from the profit equation.

The new profit equation will be:

  • Profit(x) = -x² / 20 + 230x - 4x - 72,000

  • Profit(x) = -x² / 20 + 226x - 72,000

ii) Find the first derivative and make it equal to 0:

  • Profit'(x) = -x/10 + 226 = 0
  • -x/10 + 226 = 0
  • -x + 2,260 = 0
  • x = 2,260

Then, the new maximum profit is reached when the production level is 2,260 units.

iii) Find the maximum profit by substituting x = 2,260 into the profit equation:

  • Profit (2,260) = -(2,260)² / 20 + 226(2,260) - 72,000
  • Profit (2,260) = 183,800

Hence, the maximum profit, if the government decides to tax the company $4 for each set it produces would be $183,800

iv) Find the price the company should charge for each set.

Substitute the number of units, 2,260, into the equation for the price:

  • p(2,260) = 300 - 2,260/20
  • p(2,260) = 187.

That is, the company should charge $187 per television set.

7 0
2 years ago
An auto maker estimates that the mean gas mileage of its sports utility vehicle is at least 20 miles per gallon. A random sample
Nady [450]

Answer:

Yes, we reject the auto maker's claim.

Step-by-step explanation:

H0 : μ ≥ 20

H1 : μ < 20

Sample mean, xbar = 18 ;

Sample size, n = 36

Standard deviation, s = 5

At α = 0.01

The test statistic :

(xbar - μ) ÷ s /sqrt(n)

(18 - 20) ÷ 5/sqrt(36)

-2 /0.8333333

= - 2.4

Pvalue from test statistic : Pvalue = 0.00819

Pvalue < α

0.00819 < 0.01

Hence, we reject the Null

7 0
2 years ago
Factor 9x^+12x-16 , sincerely appreciate all the help I can receive.
zheka24 [161]
The correct answer is:  [C]:  " -4 (-2x² - 3x + 4) " .
______________________________________________________
Explanation:
______________________________________________________

8x² + 12x - 16 ;  factors into:

-4 (-2x² - 3x + 4) ; which is:  Answer choice:  [C].
______________________________________________________
5 0
3 years ago
What is the probability that the first card is a kingking and the second card is a kingking if the sampling is done with​ replac
IRINA_888 [86]
You want to draw 2 kings from a 52 card deck. And you do it with replacement.
There are 4 kings in a standard deck. The probability of getting one of them is 
4/52 on the first draw.

For the second draw the probability is the same.
4/52

The probability for both happening is 
(4/52)*(4/52) = (1/13)*(1/13) = 1/169 = 0.001597
5 0
3 years ago
Other questions:
  • Round the distance traveled in kilometers to the nearest ten thousand
    5·1 answer
  • Help me with this problem asap! And if you could explain it that would be great
    5·1 answer
  • Manav is painting a rectangular room and the dimensions of this room are given by x,y and z feet. Manav takes 8 hours to paint a
    6·1 answer
  • Nick can purchase each milkshake for $2. For the first milkshake purchased Nick is willing to pay $4, for the second milkshake $
    7·1 answer
  • What is the measure of angle 5
    7·1 answer
  • Can You please help me cause I'm gangsta Simplify (5^-2)^4 ​
    5·1 answer
  • The diagram shows a convex polygon<br><br> solve for b
    15·1 answer
  • Yo, reasking bc wrong grade level, how do you find the slope as a right triangle?​
    10·2 answers
  • Easy question - will give brainly and more if correct!!!
    6·1 answer
  • Find the inequality represented by the graph.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!