If the integers have the same absolute value ... they're the same number
but with different signs ... then their sum is zero.
Example: (plus) 927 added to (negative) 927 = zero
If the integers have different absolute values ... they're different numbers with different
signs ... then their sum has the same sign as the one with the bigger absolute value.
Examples:
==> (plus) 92 added to (negative) 91
92 and 91 are 1 number apart on the number line.
The positive number is bigger than the negative number.
So the sum is +1 .
==> (plus) 35 added to (negative) 37
35 and 37 are 2 numbers apart on the number line.
The negative number is bigger than the positive one.
So the sum is -2 .
The linear equation in standard form is
.
<h3>Linear Function</h3>
An equation can be represented by a linear function. The standard form for the linear equation is: ax+b , for example, y=7x+2. Where:
a= the slope. It can be calculated for
.
b= the constant term that represents the y-intercept.
The question gives: X-intercept:3 and y-intercept: 5. Then,
- The x-intercept is the point that y=0, then the x-intercept point is (3,0).
- The y-intercept is the point that x=0, then the x-intercept point is (0,5).
With this information, you can find the slope (a).

The question gives the coefficient b since it gives the y-intercept=5.
Therefore the linear equation is :
.
Read more about the linear equations here:
brainly.com/question/2030026
#SPJ1
Answer:
Step-by-step explanation:
When the coefficients don't lend themselves to solution by substitution or elimination, then Cramer's Rule can be useful. It tells you the solutions to
are ...
- ∆ = bd -ea
- x = (bf -ec)/∆
- y = (cd -fa)/∆
Using that rule here, we find ...
∆ = 5·3 -6·2 = 3
a = (5·54 -6·41)/3 = 5·18 -2·41 = 90 -82 = 8
s = (41·3 -54·2)/3 = 41 -18·2 = 5
This math can be performed in your head, which is the intent of formulating the rule in this way.
_____
Similarly, if you expect the solutions to be small integers (as here), then graphing is another viable solution method.
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<em>Comment on the question</em>
We're sad to see than only 16 tickets were sold to the two performances by the symphonic band.
This is a problem of maxima and minima using derivative.
In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:
V = length x width x height
That is:

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:
Surface area of the square base =

Surface area of the rectangular sides =

Therefore, the total area of the cube is:

Isolating the variable y in terms of x:

Substituting this value in V:

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

Solving for x:

Solving for y:

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ftWidth = 4 ftHeight = 2 ftAnd its volume is: