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3 years ago

What is the solution of x+25=12 ?

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

7 0

Answer:

x=-13

Step-by-step explanation:

x+25=12

-25 -25

x=-13

TEA [102]3 years ago

5 0

X + 25 = 12
-25 on both sides
x = -13

Answer:
x = -13

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Which special case is represented by x? - 121?

marissa [1.9K]

Answer:

A. the difference of two squares

Step-by-step explanation:

Please use the symbol " ^ " to indicate exponentiation.

Then we have x^2 - 11^2, which is the difference of two squares:

x^2 is a square, the square of x; and 11^2 is a square, the square of 11.

A. the difference of two squares

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a² - b² = (a - b)(a + b)

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3 years ago

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Brian has a gift card with a $250 balance. He buys several video games that cost $33 each. After the purchases, his gift card ba

Leno4ka [110]

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Step-by-step explanation:

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2 years ago

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Consider three events A, B and C with following properties.

lisov135 [29]

By the inclusion/exclusion principle,

$\mathbb P(D)=\mathbb P(A\cup B\cup C)$
$\mathbb P(D)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\bigg(\mathbb P(A\cap B)+\mathbb P(A\cap C)+\mathbb P(B\cap C)\bigg)+\mathbb P(A\cap B\cap C)$
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So the union of A, B, and C does not constitute the entire sample space.

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3 years ago

Which equation matches the graph of the absolute value function seen here?

nignag [31]

use a calculator instead of asking

7 0

3 years ago

Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation t

horrorfan [7]

Answer:

C.(3|-4)

Step-by-step explanation:

Given the vector:

$\left[\begin{array}{ccc}4\\3\end{array}\right]$

The transformation Matrix is:

$\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]$

The image of the vector after applying the transformation will be:

$\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right]$

The correct option is C

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3 years ago