Ask question

Ask question

All categories

3 years ago

12

a school is building a square shed that is 5 meters long on each side however before the construction begins school management d

ecides to halve the length of the shed on all sides by how much would the area of the square shed decrease?

1 answer:

nadezda [96]3 years ago

7 0

It would decrease 2.5

You might be interested in

The distance from Jason’s house to school is 0.5 kilometers.What is the distance in meters?

inn [45]

Answer:

Step-by-step explanation:

So we know that we have 1000 m in 1 km.

So convert 0.5 km to m we multiply 0.5 by 1000

0.5*1000 = 500

7 0

3 years ago

Read 2 more answers

Indicate the answer choice that best completes the statement or answers the question.

Tema [17]

Answer:

C

Step-by-step explanation:

m<2:

180 - 60 - 48 = 72

Vertical angle thm:

m<1 = 48

m<3:

180 - 62 - 48 = 70

6 0

3 years ago

Consider the functions:

jolli1 [7]

The x and y axis so that’s why it’s true

5 0

3 years ago

Read 2 more answers

The line 2x + 3y = -6 intersects the x axis at (a,0) and the y axis at (0,b) what is a + b ?

USPshnik [31]

2x + 3y = -6 (Subtract 2x from both sides)
3y = -2x - 6 (Divide both sides by 3 to isolate x) which will give you y = -2/3x - 2 and this graphed would cross the x-axis at (-3,0) and the y-axis at (0, -2). So a + b = -5

3 0

3 years ago

Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the

KonstantinChe [14]

Answer:

The center of the circle is

$(-\frac{3}{2},2)$

Step-by-step explanation:

Let the equation of the circle be

$x^2+y^2+2ax+2by+c=0$ , where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

$0^2+0^2+2a(0)+2b(0)+c=0$

$\implies c=0$

B(-3,0)

$(-3)^2+0^2+2a(-3)+2b(0)+c=0$

$\implies 9+0-6a+0+c=0$

$\implies -6a+c=-9$

But c=0

$\implies -6a=-9$

$\implies a=\frac{3}{2}$

C(1,2)

$1^2+2^2+2a(1)+2b(2)+c=0$

$1+4+2a+4b+c=0$

$2a+4b+c=-5$

Put the value of 'a' and 'c' to find 'b'

$2(\frac{3}{2})+4b+0=-5$

$3+4b+0=-5$

$4b=-5-3$

$4b=-8$

b=-2

Hence the center of the circle is

$(-\frac{3}{2},2)$

8 0

3 years ago