Answer:
X inactivation
Explanation:
The female mammals have double the number of X-linked genes as compared to their counterpart males. During early embryonic development, either the maternal or paternal X chromosome in all the cells of a female is inactivated by the process of heterochromatinization. The inactivated X chromosome is present in the form of a Barr body. This inactivation of the X chromosome is a random event.
The inactivated X chromosome of a cell remains in the same state in all of its progeny cells. In this way, the process of X inactivation balances the dosages of X-linked genes between males and females.
Answer:
8 black guinea pigs
Explanation:
We're given that the black fur color is the dominant trait, meaning that this problem deals with complete dominance. In complete dominance, having just one allele is enough to express a certain phenotype. So let's say the female guinea pig has the genotype BB for homozygous black. The male would be bb since he's homozygous white, and the color white is recessive. Cross this and you get the genotypes Bb. But remember that even having one dominant allele will be sufficient to express the dominant phenotype. So all guinea pigs shall be black in fur color.
Germ cell's I believe. These are cells that includes half your genome in order to reproduce.
Phone
Car
Shoes
Desk
Any inanimate object :)