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ella [17]
1 year ago
7

Normal or natural variations in the quality of production output that are due purely to chance are _____.

Mathematics
1 answer:
nydimaria [60]1 year ago
6 0

Normal or natural variations in the quality of production output that are due purely to chance are common causes.

According to the statement

we have to tell about the that cause which effect the quality and production output in the normal and natural variation.

So, For this purpose, we know that the

Common cause variation is present when the control chart of a process measure shows a random pattern of variation with all points within the control limits. When a control chart shows common cause variation, a process measure is said to be in statistical control or stable.

And due to this cause there is a lot of effect on the natural variations in the quality of production output.

So, Normal or natural variations in the quality of production output that are due purely to chance are common causes.

Learn more about common cause variation here

brainly.com/question/28040185

#SPJ4

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There are four boys and eight girls in a class. The teacher randomly selects three different students to answer questions. The f
umka21 [38]

The probability of the given condition is 28/165.

Given that, there are four boys and eight girls in a class.

We need to find the probability of the given question.

<h3>What is probability?</h3>

The probability is defined as the chances of happening of any random event or the possibility of happening of any event is called the probability.

The teacher randomly selects three different students to answer questions.

The first is the student is a girl, the second student is a boy, and the third student is a girl.

The total number of students=12, the number of boys=4 and the number of girls=8.

Now,

Step 1: The first student is a girl=8/12

Step 2: The second student is a boy=4/11

Step 3: The third student is a girl=7/10

In the first step, you select one of 8 girls among 12 students.

In the second step, you select one of 4 boys among the remaining 11 students.

In the third step, you select one of the remaining 7 girls among the remaining 10 students.

Thus, probability=(8/12)×(4/11)×(7/10)=28/165

Therefore, the probability of the given condition is 28/165.

To know more about probability visit:

brainly.com/question/24756209

#SPJ1

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Step-by-step explanation:

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