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Sonbull [250]
3 years ago
5

PLZZZZZZZ HEELLLLPPPPP

Mathematics
2 answers:
malfutka [58]3 years ago
6 0

Answer:

y ≤ 0

Step-by-step explanation:

Just solve the equation as you normally would and you get y ≤ 0

Hope this helps!

NARA [144]3 years ago
5 0
Y is less than or unequal to
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The product of a number and -3, increased by 8, is 20
natita [175]

answer:

-4

Step-by-step explanation:

-3x+8= 20

-8 -8

-3x = 12

÷-3. = ÷-3

x = -4

3 0
3 years ago
Пожалуйста помогите с решением
zubka84 [21]

Answer:

( x, y) =

65 \ \frac{15}{11}

this is your answer

3 0
2 years ago
Simplify (3^-2) ^4 what is it
Lana71 [14]

Answer:

1/6561

Step-by-step explanation:

3^-2 = 1/9

1/9^4 = 1/6561

5 0
3 years ago
Read 2 more answers
If p is the midpoint of line xy, xp=11-6b and py=6-b, find xp
MariettaO [177]
Since p is the midpoint then xp and pay must equal each other
So, 11-6b=6-b
Solve for b
11-6b=6-b
-6 -6
5-6b=-b
+6b +6b
5=5b
b=1

xp=11-6(1)
xp=5
5 0
3 years ago
Resolve into partial fractions<br><br>​
lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

1)

\frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A}{2 - x}  +  \frac{B}{x - 3}  \\  \\  \therefore \:  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)}   \\  \\ \therefore \:  11 + x = Ax - 3A + 2B - Bx \\  \\  \therefore \: 11 + x = - 3A  + 2B  + Ax -  Bx\\  \\  \therefore \: 11 + x = - 3A  + 2B  + (A - B)x \\  \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\  \therefore \: A  =  B  +  1.....(1) \\  \\  -  3A  + 2B = 11....(2) \\  from \: eq \: (1) \: and \: (2) \\  - 3(B  +  1) + + 2B = 11 \\  \\ - 3B   - 3  + 2B = 11 \\  \\  - B = 11 + 3 \\  \\ B =  - 14  \\ A  =   - 14 +  1 =  - 13 \\  \\  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{ - 13}{2 - x}  +  \frac{ - 14}{x - 3} \\  \\ \frac{11 + x}{(2 - x)(x - 3)}  = -   \frac{ 13}{2 - x}   -  \frac{ 14}{x - 3}

2)

\frac{12x + 11}{x^2 +x - 6}

=\frac{12x + 11}{x^2 +3x-2x - 6}

=\frac{12x + 11}{x(x +3) -2(x +3)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A}{(x +3)}+\frac{B}{(x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A(x-2)+B(x+3)}{(x-2)(x+3)}

\therefore 12x + 11 = A(x-2)+B(x+3)

\therefore 12x + 11 = Ax-2A+Bx+3B

\therefore 12x + 11 = Ax+Bx-2A+3B

\therefore 12x + 11 = (A+B) x-2A+3B

Equating like terms on both sides:

A + B = 12\implies A = 12-B... (1)

- 2A + 3B = 11... (2)

Solving equations (1) & (2), we find:

A = 5, B = 7

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{5}{(x +3)}+\frac{7}{(x - 2)}

3 0
3 years ago
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