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Illusion [34]
2 years ago
14

Please I need the asnwer with the explanation

Mathematics
1 answer:
Virty [35]2 years ago
8 0

Answer:

  a. 400 m

  b. 46.56 m

  c. 461 m

Step-by-step explanation:

The perimeter is the sum of the circumference of two semicircles and the two straight sections. Two semicircles add up to one circle.

<h3>Circumference</h3>

The circumference of a circle is given by the formula ...

  C = 2πr

For an inner radius of 36.8 m, the circumference of the inner circle is ...

  C = 2π(36.8 m) = 73.6π m

The outer perimeter will have a radius that is the sum of the inner radius and the width of 8 track lanes.

  r = 36.8 m + 8(1.22 m) = 46.56 m . . . . . . . . . outer semicircle radius

The circumference of the outer circle is ...

  C = 2π(46.56 m) = 93.12π m

<h3>Straight sections</h3>

The straight sections are the same length on both perimeters. The sum of the two straight section lengths is ...

  2 × 84.39 m = 168.78 m

<h3>a. Inner Perimeter</h3>

The inner perimeter is the sum of the inner circumference and the length of the straight sections:

  P = 73.6π m + 168.78 m ≈ 231.2 m + 168.8 m = 400 m

The inner perimeter is about 400 meters.

<h3>b. Outer Radius</h3>

Above, we found the radius at the outside edge of the track to be 46.56 m.

The outer radius is 46.56 meters.

<h3>c. Outer Perimeter</h3>

The outer perimeter is the sum of the outer circumference and the length of the straight sections:

  P = 93.12π m +168.78 m ≈ 292.5 m + 168.8 m ≈ 461 m

The outer perimeter is about 461 meters.

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Step-by-step explanation:

We don't know what notation you're used to seeing for rotations. Here. we'll use the form [degrees CCW, (center)]. (CW angles are negative.) In any rotation, the center is the point that is invariant (remains in the same place)

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If you have trouble visualizing these rotations, you might find it useful to trace the arrow on a piece of (semi-)transparent medium (plastic or tracing paper) so that you can move it as required to match the descriptions in the problem statement. A pin, or a dot on your tracing, can serve to fix the center of rotation. A little hands-on never hurts in math and geometry.

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