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lora16 [44]
3 years ago
13

An isosceles triangle has a base of 8 inches and legs measuring 12 inches how wide is the base of a similar triangle with legs m

easuring 36 inches
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0
If the triangles are similar, the base should be 24 inches. The legs on the first triangle are 12 inches. To get 36 inches (the other triangle), we multiply 12 by 3. 12 x 3 = 36. Because you did that to the legs, you must also do it to the base. 8 x 3 = 24. Therefore, the base of the second triangle is 24 inches.
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Can someone help me with the First question ?
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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Give the following equations determine if the lines are parallel perpendicular or neither
GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

\frac{6x-5y}{2}=x+1

Cross multiply both sides of the equation.

6x-5y=2(x+1)6x-5y=2x+2

Subtract 6x on both sides of the equation.

6x-5y-6x=2x+2-6x-5y=-4x+2

Divide both sides of the equation by -5.

-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}y=\frac{4}{5}x-\frac{2}{5}

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

-4y-x=4x+5

Add x on both sides of the equation.

-4y-x+x=4x+5+x-4y=5x+5

Divide both sides of the equation by -4.

\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}y=-\frac{5}{4}x-\frac{5}{4}

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5 0
1 year ago
(please show work) offering 24 points !
larisa86 [58]
V=hpir^2
SA=2pir^2+2hpir


a.
SA=2pi9^2+2*36pi9
SA=2pi81+72pi9
SA=162pi+648pi
SA=810pi in^2


b.
aprox pi=3.14
810*3.14=2542.4cm^2


c.
V=36pi9^2
V=36pi81
V=2916pi in^3

d. 3.14=pi
2916*3.14=9156.24 in^3
8 0
3 years ago
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