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lora16 [44]
3 years ago
13

An isosceles triangle has a base of 8 inches and legs measuring 12 inches how wide is the base of a similar triangle with legs m

easuring 36 inches
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0
If the triangles are similar, the base should be 24 inches. The legs on the first triangle are 12 inches. To get 36 inches (the other triangle), we multiply 12 by 3. 12 x 3 = 36. Because you did that to the legs, you must also do it to the base. 8 x 3 = 24. Therefore, the base of the second triangle is 24 inches.
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The ratio of length to width (measured in inches) in a rectangle is 4∶7. find the length of the rectangle if the area is known t
Len [333]
Hey mate
here is your answer

length and width are given in the ratio are ;(4:7)
area of rectangle = (l×b)
therefore,
4x×7x=700
28x^2=700
x^2=700/28
x^2=25
x=5
length =4x=4×5=20, lenght =20 and width =7x so, 7×5=35 width.....
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Step-by-step explanation:

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skelet666 [1.2K]

Answer:

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Step-by-step explanation:

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2 years ago
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Please answer this correctly
Alex Ar [27]

Answer:

Area of the figure = 254.5 cm²

Step-by-step explanation:

<u><em>Area of rectangle = Length × Width</em></u>

<u><em>Area of triangle = 1/2(base × Height)</em></u>

<em>Dividing the figure into parts for convenience</em>

So,

Rectangle 1  (the uppermost):

4 × 6 = 24 cm²

Rectangle 2 (below rectangle 1):

15 × 8 = 120 cm²

Rectangle 3 (with rectangle 2):

11 × 4 = 44 cm²

Triangle 1 :

1/2(7 × 19) = 133/2 = 66.5 cm²

<em>Now adding up all to get the area of the figure:</em>

Area of the figure = 24 + 120 + 44 + 66.5

Area of the figure = 254.5 cm²

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3 years ago
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