Answer: if im not wrong it would be 1583/1000
Step-by-step explanation:
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
I found the corresponding image. Pls. see attachment.
<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is
2 (translation and rotation). A
rotation translation must be used to make the two polygons coincide.
A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is
a translation 2 units down and a 90° counterclockwise rotation about point D </span>
Answer:
No, none of the number need to be 48 for the mean to be 48. To get a mean, you add up all the number and divide it by the amount of numbers.
Example:
the mean of 10, 79, 42, 88, 19, and 50 is 48, but the actual number 48 was not part of the set.
10 + 79 + 42 + 88 + 19 + 50 = 288
288 ÷ 6 = 48