Answer:
See below
Step-by-step explanation:
Let the following symbols stand for the cost of each fish type:
A = Albacore
B = Baracuda
C = Carp
D = Dogfish
E = Eel
F = Flounder
G = Gar
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We are told the following (numbers are in $):
A+B = 21
B+C = 24
C+D = 32
D+E = 37
E+F = 31
F+G = 25
G+A = 26
I count 7 unknowns (A,B,C,D,E,F,G) and 7 equations. In principle, the answers should therefore be possible [it can be a little tedious]. I'll rewrite each expression so that only one variable remains on the left side:
A = 21 - B
B = 24 - C
C = 32 - D
D = 37 - E
E = 31 - F
F = 25 - G
G = 26 - A
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Now find combinations of these expressions that will allow us to (slowly) remove one of the two unknowns.
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A = 21 - B
A = 21 - (24 - C)
A = C - 3
A = (32 - D) - 3
A = 29 - D
A = 29 - (37 - E)
A = E - 8
A = (31 - F) - 8
A = 23 - F
A = 23 - (25 - G)
A = G - 2
A = (26 - A) - 2
2A = 24
<u>A = 12</u> We found one price. <u>Albacore cost $12 each.</u>
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Now use A = 12 to find B
A = 21 - B
12 = 21 - B
<u>B = 9 </u> <u> Barracuda cost $9 each</u>
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And so on:
B+C = 24
9+C = 24
<u>C = 15</u> <u>Carp are $15 each</u>
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C+D = 32
15+D = 32
<u>D = 17</u> <u>Dogfish are $17 each</u>
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D+E = 37
17+E = 37
<u>E = 20</u> <u>Eels are $20 each [Not worth it]</u>
E+F = 31
20+F = 31
<u>F = 11</u> <u> Flounder are $11 each</u>
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F = 25 - G
11 = 25 - G
<u>G = 14</u> <u>Gar are $14 each</u>
<h2><em>Wheh. I'm going fishing.</em></h2>
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