Answer:
- x = 30°
- DB = 26
- AD = BC = AB = DC = 7
Step-by-step explanation:
- <em>Diagonals of a square are congruent and perpendicular and bisect each other</em>
<h3>Q4</h3>
m∠AEB = 3x
m∠AEB = 90°
<h3>Q5</h3>
AE = 3x - 2
EC = 2x + 3
- AE = EC
- 3x - 2 = 2x + 3
- 3x - 2x = 3 + 2
- x = 5
DB = EC = 2(AE) = 2(3*5 - 2) = 2(13) = 26
<h3>Q6</h3>
<u>AD and BC are the sides, which are equal</u>
- 2x - 1 = 5x - 13
- 5x - 2x = 13 - 1
- 3x = 12
- x = 4
AD = BC = AB = DC = 2*4 - 1 = 7
aP and BQ are the bisectors of the two alternate interior angles formed by the intersection of a transversal t with parallel lines l and m .. Show that AP || BQ. .its a example i just gave.
thanx
for doubt plese give me a messageee
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Answer:</u></h2><h2>
</h2><h2 /><h2><u>Solution Steps:</u></h2>
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<h3>(Below)</h3>
Answer: si esta correcta 1/6
Step-by-step explanation:
Espero te ayude
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