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miv72 [106K]
2 years ago
13

How do you simplify(n!)^2/(n+1)!(n-1)!

Mathematics
1 answer:
ANTONII [103]2 years ago
5 0
We haven n! = (n-1)! x n and (n+1)! = n! x (n + 1);
Then, (n!)^2 = n! x n! = n! x (n-1)! x n;
And (n+1)!(n-1)! = n! x (n + 1) x (n-1)!;
Finally, [n! x (n-1)! x n] / [n! x (n + 1) x (n-1)!] = (n+1)/n;
You might be interested in
What is the AREA of this figure?
elena-14-01-66 [18.8K]

Answer:

532m squared is the answer

Step-by-step explanation:

Split the shape into two shapes

one will be a square and the other one a triangle

1) since the length and the width of the square is 18m just Multiply

18x18=324m squared

2) look carefully the width of the square you split is equal to the base of the triangle, so you connect the 18 and the 8 together.

18+8=26m squared

3) Now solve the triangle since you know the height which is 16m squared.

A=lw/2

26x16=416

416 divided by 2 is 208

4) finally just Add

208+324=532m squared

Hopes this helps!

7 0
3 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
2 years ago
Mary moves 3 steps backward as she dances​
IgorLugansk [536]
Where’s the question????
3 0
2 years ago
In the XY coordinate plane, the slope of a line is 4 and it passes through the point (1,3). Find the equation of a line that is
Sergeeva-Olga [200]

Answer:

E?

Step-by-step explanation:

I'm sorry of this answer is wrong

7 0
3 years ago
6 in<br> 5 in<br> 14 in<br> Area =
Hunter-Best [27]

Answer:

184

Step-by-step explanation:

2*(6*5+6*14+5*14)=184

3 0
3 years ago
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