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2 years ago

How do you simplify(n!)^2/(n+1)!(n-1)!

1 answer:

5 0

We haven n! = (n-1)! x n and (n+1)! = n! x (n + 1);
Then, (n!)^2 = n! x n! = n! x (n-1)! x n;
And (n+1)!(n-1)! = n! x (n + 1) x (n-1)!;
Finally, [n! x (n-1)! x n] / [n! x (n + 1) x (n-1)!] = (n+1)/n;

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Read 2 more answers

What is the measure of WUX in Circle V ?

Alja [10]

Answer:

$arc\ WUX=120^o$

Step-by-step explanation:

<u><em>The complete question is:</em></u>

In circle V, angle WXZ measures 30°. Line segments WV, XV, ZV, and YV are radii of circle V. Circle V is shown. Line segments W V, X V, Z V, and Y V are radii. Lines are drawn from point W to point X and from point Z to point Y to form secants. Point U is on the circle between points W and X. What is the measure of Arc W U X in circle V?

The picture of the question in the attached figure

step 1

Find the measure of angle XWV

we know that

The triangle VWX is an isosceles triangle, because has two equal sides (VX=VW)

we have

$m\angle WXZ=30^o\\m\angle WXV=m\angle WXZ$

$m\angle WXV=30^o$

Remember that an isosceles triangle has two equal interior angles

step 2

Find the measure of angle WVX

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle\ WVX+m\angle XWV+m\angle WXV=180^o$

substitute the given values

$m\angle WVX+30^o+30^o=180^o\\m\angle WVX=180^o-60^o=120^o$

step 3

Find the measure of arc WUX

we know that

$arc\ WUX=m\angle WVX$ ----> by central angle

we have

$m\angle WVX=120^o$

therefore

$arc\ WUX=120^o$

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3 years ago

Write an equation in slope intercept form of the line containing the points (-2,5) and (9,-6)

otez555 [7]

(-2,5)(9,-6)
slope(m) = (-6-5) / (9 - (-2) = -11/11 = -1

y = mx + b
slope(m) = -1
(-2,5)...x = -2 and y = 5
now we sub and solve for b, the y int
5 = -1(-2) + b
5 = 2 + b
5 - 2 = b
3 = b

so ur equation in slope intercept form is : y = -x + 3

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3 years ago

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nadya68 [22]

Answer:

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Step-by-step explanation:

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2 years ago