A boy stands 1 meter away from a lamppost. He is 1.8 meters tall and casts a shadow 2 meters long in the light from the lamp
The diagram is attached below using the given information
We have two similar triangle
Triangle ACD is similar to triangle ABE. So the sides are in proportional

AC = AB + BC = 3m

2x = 1.8 * 3 (cross multiply)
2x = 5.4
Divide by 2 on both sides
x = 2.7
Height of Lamppost is 2.7 meter
Answer:
y = 1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-3y + 14 + y = 12
<u>Step 2: Solve for </u><em><u>y</u></em>
- Combine like terms [Addition]: -2y + 14 = 12
- [Subtraction Property of Equality] Subtract 14 on both sides: -2y = -2
- [Division Property of Equality] Divide -2 on both sides: y = 1
Answer:
x + 3y = 21
Step-by-step explanation:

Equation of the line: y =mx+ b

Multiply the equation by 3
3y = -x + 21
x + 3y = 21
I just graphed the table next to the graph of g and compared the two.
The y-intercept of f is (0,8) and the y-intercept of g is (0, -2). So f is GREATER THAN the y-intercept of g.
Now to do the average rate of change, I see from the interval [-6,-3] that f is decreasing and for g it is increasing. Thus f is LESS THAN the average rate of change of g.