The test statistic for the hypothesis would be 1.413.
Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.
The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.
Hypothesis:
Null hypothesis:H₀:μ=13
Alternative hypothesis:Hₐ:μ>13
Here, μ be the mean weight loss of all participants.
n=30,
Degree of freedom n-1=30-1=29
=13.8 and s=3.1
To test the null hypothesis H₀, the value of test static would be calculated as follows:
Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.
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He isn’t correct because both 0.4 and 0.400 is the equivalent number
312.5 x 13. Which is <span>4062.5. Then add 1562.5 to get 5625. So by 1998 there would be 5625 bald eagle pairs</span>
Answer:
yah why
Step-by-step explanation:
Set each set of parentheses to 0 and solve for x.
X—6 = 0
X = 6
X + 5 = 0
X = -5
X-9 = 0
X = 9
The zeros are 6, -5, 9