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3 years ago

HELP! Quadrilateral ABCD is inscribed in the circle below.

Mathematics

2 answers:

hjlf3 years ago

6 0

I don’t understand what you mean by the quadrilateral ABCD is inscribed in the circle below

myrzilka [38]3 years ago

3 0

Answer:

Step-by-step explanation:

If a quadrilateral is inscribed in a circle with all four edges touching the circumference of the circle, then the opposite angles are supplementary. This means that the sum of the opposite angles is 180 degrees. Therefore,

Angle B + angle D = 180

Angle A + angle C = 180

3x + x + 20 = 180

4x = 180 - 20 = 160

x = 160/4

x = 40

Angle A = 2 × 40 + 78 = 158 degrees

Angle B = 3 × 40 = 120 degrees

Angle C = 180 - 158 = 22 degrees

Angle D = 40 + 20 = 60 degrees

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Use the following matrices, A, B, C and D to perform each operation.

Vinvika [58]

Step-by-step explanation:

$A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]$

$B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]$

$C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]$

$D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]$

$1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]$

$2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]$

$3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]$

$4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]$

$5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}$

6 0

3 years ago

Jerry paid $99.30 for 6 shirts.how much did jerry pay for each shirt?

Over [174]

The answer is 16.55

Divide $99.30 by 6 and you get your answer!

I hope this helps :)

5 0

3 years ago

Can someone help me please

rjkz [21]

Answer:

I'm gonna go with D

Step-by-step explanation:

If it's wrong meh bad

3 0

2 years ago

Read 2 more answers

Create and solve a linear equation that represents the model, where squares and triangles are shown evenly balanced on a balance

Rina8888 [55]

Let the weight of triangle be x units. You are given that the weight of square is 1 unit.

1) On the left side of the balanced beam you can see 3 triangles and 5 squares. The weight on left side is 3·x+5·1=3x+5 units.

2) On the right side of the balanced beam you can see 2 triangles and 7 squares. The weight on right side is 2·x+7·1=2x+7 units.

3) If the whole system is balanced, then the weights on left and right sides are equal:

3x+5=2x+7.

Solve this equation:

3x-2x=7-5,

x=2 units.

Answer: option A

8 0

2 years ago

(2k 3 +6k+1)−(2k 2 +1). Simplify and put into standard form

Rzqust [24]

Answer:

$2k^3-2k^2+6k$ .

Step-by-step explanation:

We have been given an expression and we are asked to simplify our given expression.

$(2k^3+6k+1)-(2k^2+1)$

Using order of operations (PEMDAS) we will remove parenthesis first.

After removing parenthesis our expression will be,

$2k^3+6k+1-2k^2-1$

After canceling out 1 with -1 we will get,

$2k^3+6k-2k^2$

So our given expression simplifies to $2k^3+6k-2k^2$ .

Let us write our expression in standard form. Since our expression is a polynomial and to write any polynomial in standard form, we write each term in order of degree, from highest to lowest, left to right.

Upon putting our polynomial into standard form we will get,

$2k^3-2k^2+6k$

Therefore, after simplifying and putting our given expression in standard form we get our final expression as: $2k^3-2k^2+6k$ .

6 0

3 years ago