Answer:
5
Step-by-step explanation:
We have been given that the point 
lies on the curve 
. Q is the point 
. We are asked to find the slope of the secant line 
for 
.
Let us find y-coordinate corresponding to for point P as:
Now, we will use slope formula to find required slope.
Let point 
and point 
.
Using these points in slope formula, we will get:
Therefore, the slope of the line PQ is 5.
3(x-1)-8=4(1+x)+5
One solution was found :
x = -20
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*(x-1)-8-(4*(1+x)+5)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((3•(x-1))-8)-(4•(x+1)+5) = 0
Step 2 :
Equation at the end of step 2 :
(3 • (x - 1) - 8) - (4x + 9) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
-x - 20 = -1 • (x + 20)
Equation at the end of step 4 :
-x - 20 = 0
Step 5 :
Solving a Single Variable Equation :
5.1 Solve : -x-20 = 0
Add 20 to both sides of the equation :
-x = 20
Multiply both sides of the equation by (-1) : x = -20
One solution was found :
x = -20
hope this is wht u wanted
B because if x is negative you always move to the left when plotting a point and if the y is positive you’ll always move up the y-axis to plot the point
