Answer:
The system of equations is:
x + y = 15
xy = 15
Step-by-step explanation:
solve the first for y and substitute in the second:
y = 15-x
x(15-x) = 15
15x - x� = 15
15x - x� - 15 = 0
-x� + 15x - 15 = 0
x� - 15x + 15 = 0
2/5 of 30 = 12
30 + 12 = 42
£42
I know the answers but I hate simplifying
40) 9y-12
42) -3x+3y-5
Answer:
Exactly two distinct zeros
Step-by-step explanation:
y = 2(x-1) (x + 4)
Plug y = 0
0 = 2(x-1) (x + 4)
0/2 = (x-1) (x + 4)
(x-1) (x + 4) = 0
(x-1) = 0 or (x + 4)= 0
x = 1 or x = - 4
Here, x has two distinct roots, therefore given quadratic relation has Exactly two distinct zeros.
