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Naily [24]
2 years ago
13

Simplify the following expression to remove negative exponents.

Mathematics
1 answer:
katrin2010 [14]2 years ago
7 0

The expression \rm \frac{(j^{-3})(f^5)}{(c^2)(g^{-1})} is equivalent to the expression \frac{(f^5)(g^{1})}{(c^2)(j^{3})}. Then the correct option is B.

<h3>What is an equivalent expression?</h3>

The equivalent is the expressions that are in different forms but are equal to the same value.

Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.

The expression is given below.

\rm \rightarrow \dfrac{(j^{-3})(f^5)}{(c^2)(g^{-1})}

We know that a⁻¹ = 1/a and 1/a⁻¹ = a.

Simplify the expression. Then the expression will be

\rm \rightarrow \dfrac{(j^{-3})(f^5)}{(c^2)(g^{-1})}\\\\\\\rm \rightarrow \dfrac{(f^5)(g^{1})}{(c^2)(j^{3})}

The expression \rm \frac{(j^{-3})(f^5)}{(c^2)(g^{-1})} is equivalent to the expression \frac{(f^5)(g^{1})}{(c^2)(j^{3})}.

Then the correct option is B.

More about the equivalent link is given below.

brainly.com/question/889935

#SPJ1

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what number is 28% of 25

Is means equals and of means multiply

N = 28% of 25

Change to decimal form

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3 years ago
Im Triggered Pls Dont DELETE!
stepladder [879]

I'm assuming you mean f(x) = (e^x + 5x)^2, not f(x) = (e x + 5x)2, like your prompt suggests.


First, let's figure out what rule we can use. A likely noticeable one is the Power Rule, which says the following:

\dfrac{d}{dx} [u^a] = a(u)^{a-1} du


Applying this, we can solve for the derivative:

f'(x) = 2(e^x + 5x) (e^x + 5)

  • Apply the Power Rule

While you can simplify the expression to your liking, I believe that this form is not overly complex and will thus leave it as is.


Thus, our answer is:

f'(x) = \boxed{2 (e^x + 5x)(e^x + 5)}

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