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3 years ago

Is this the correct answer?

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

30kx-6kx=8
24kx=8
x=8/(24k)
x=1/(3k)
so the answer should actually be D

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Complete the solution of the equation. Find<br> the value of y when x equals -4.<br> x + 3y = 14

LekaFEV [45]

Answer:

y = 6

Step-by-step explanation:

-4 + 3y = 14

+4 +4

3y = 18

---- ----

3 3

y = 6

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3 years ago

If 2x^2-5x+7 is subtracted from x^2+2x-11, what is the leading coefficient?

guajiro [1.7K]

Answer:

-1

Step-by-step explanation:

2x² - 5x + 7 is subtracted <em>from </em>x² + 2x - 11, so

(x² + 2x - 11) - (2x² - 5x + 7)

x² + 2x - 11 - 2x² + 5x -7 (Distribute the negative)

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The leading coefficient is the coefficient of the first term, so it is -1.

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3 years ago

Algebra 2 Math question Grade 11

Paha777 [63]

Answer:

$\displaystyle y=\frac{4}{5}x+\frac{13}{5}$

Step-by-step explanation:

The equation of the line in slope-intercept form is:

y=mx+b

Where m the slope of the line and b the y-intercept.

When two points are given, it's convenient to calculate the slope first.

Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

The points are (3,5) and (-2,1):

$\displaystyle m=\frac{1-5}{-2-3}=\frac{4}{5}$

The equation is now:

$\displaystyle y=\frac{4}{5}x+b$

To calculate b, we use any of the given points and solve for b. Use (3,5):

$\displaystyle 5=\frac{4}{5}3+b$

Operate:

$\displaystyle 5=\frac{12}{5}+b$

Solve:

$\displaystyle b=5-\frac{12}{5}=\frac{13}{5}$

The required equation of the line is:

$\boxed{\displaystyle y=\frac{4}{5}x+\frac{13}{5}}$

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3 years ago

29/5 converted to mixed number

lora16 [44]

If you would like to convert 29/5 to a mixed number, you can do this using the following steps:

29/5 = 5 4/5

The correct result would be 5 4/5.

7 0

3 years ago

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Write the expression as a single natural logarithm. 3 In m + 4 Inn

skad [1K]

Answer:

$ln( {m}^{3} {n}^{4} )$

Step-by-step explanation:

$\alpha ln(x) = ln( {x}^{ \alpha } )$

$ln( {m}^{3} ) + ln( {n}^{4} )$

$ln(a) + ln(b) = ln(ab)$

$ln( {m}^{3} {n}^{4} )$

8 0

3 years ago

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