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2 years ago

Please Help!!!

Mathematics

1 answer:

Sladkaya [172]2 years ago

3 0

Answer:

Step-by-step explanation:

9.05737

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On a city map 3/4 inch corresponds to 7 1/2 miles bonnie drives from her house to a movie theater and then from a movie theater

Juliette [100K]

Answer:

Option D: $12\frac{1}{2}$ is the correct answer.

Step-by-step explanation:

Given that:

3/4 inches on map are equal to $7\frac{1}{2}$ miles

We will find the unit rate in term of inches.

$\frac{3}{4}\ inches = 7\frac{1}{2}\\\\Unit\ rate = \frac{15}{2}*\frac{4}{3}\ miles\\\\Unit\ rate = 10\ miles\ per\ inch$

Total distance covered by Bonnie according to map;

Total distance = $\frac{1}{2}+\frac{3}{4} = \frac{2+3}{4}$

Total distance = $\frac{5}{4}\ miles$

Actual distance = $\frac{5}{4}*10 = \frac{25}{2}\ miles \\$

Actual distance = $12\frac{1}{2}\ miles$

Hence,

Option D: $12\frac{1}{2}$ is the correct answer.

8 0

3 years ago

Lines c and d are parallel lines cut by transversal p.

lilavasa [31]

Answer:

Option (B).

Step-by-step explanation:

Here there are two parallel lines c and d cuts by a transversal p.

The angles are formed as shown in diagram.

Here,

$\angle 1 = \angle 7 (alternate)\\\\\angle 2 = \angle 6 (corresponding)\\\\\angle 3 = \angle 5 (alternate)\\\\\angle 5 = \angle 7 (alternate)$

So, the option (B) is correct.

5 0

3 years ago

8090 [49]

Answer:

James bought 11 good tickets and 5 bad tickets.

Step-by-step explanation:

Given that:

Cost of each good ticket = $8

Cost of each bad ticket = $5

Total amount spent = $113

Total tickets bought = 16

Let,

x be the number of good tickets bought

y be the number of bad tickets bought

x+y=16 Eqn 1

8x+5y=113 Eqn 2

Multiplying Eqn 1 by 5

5(x+y=16)

5x+5y=80 Eqn 3

Subtracting Eqn 3 from Eqn 2

(8x+5y)-(5x+5y)=113-80

8x+5y-5x-5y=33

3x=33

Dividing both sides by 3

$\frac{3x}{3}=\frac{33}{3}\\x=11$

Putting x=11 in Eqn 1

11+y=16

y=16-11

y=5

Hence,

James bought 11 good tickets and 5 bad tickets.

3 0

2 years ago

xYou volunteer to help drive children at a charity event to the zoo, but you can fit only 6 of the 16 children present in your

brilliants [131]

There are 8008 groups in total, in other to drive the children

<h3>How to determine the number of groups?</h3>

From the question, we have

Total number of children, n = 16
Numbers to children at once, r = 6

The number of group of children that could be carried at once is calculated using the following combination formula

Total = ⁿCᵣ

Where

n = 16 and r = 6

Substitute the known values in the above equation

Total = ¹⁶C₆

Apply the combination formula

ⁿCᵣ = n!/(n - r)!r!

So, we have

Total = 16!/10!6!

Evaluate

Total = 8008

Hence, the number of groups is 8008