A 95% confidence interval for the proportion of non-fatal accidents involving a distracted driver using some kind of electronic device is 62.5%<x<71.61%
The 95% confidence interval for the proportion is expressed according to the formula;

p is the proportion = 268/400 = 0.67
z is the 95% z-score = 1.96
n is the sample space = 400
Substitute the given parameters into the formula to have:

Hence a 95% confidence interval for the proportion of non-fatal accidents involving a distracted driver using some kind of electronic device is 62.5%<x<71.61%
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Answer:
I can't see that very good, but I counted 8 units.
Step-by-step explanation:
Personally I think the answer would be c. Cross multiplication
Step-by-step explanation:
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Answer:
3 miles per hour
Step-by-step explanation:
he runs 1/3 mile in 1/9 of an hour
then
he runs (we multiply both sides by 9)
9×(1/3) mile in 9×(1/9) of an hour
then
he runs
(9/3) mile in (9/9) of an hour
then
he runs
3 mile in 1 hour