The chart shows the low temperature each day in International Falls, Minnesota, during the month of February 2009. What was the
median low temperature in International Falls for the first week of the month?
2 answers:
Answer:
The median of low temperature in International Falls for the first week of the month is -8.
Step-by-step explanation:
From the given table it is noticed that the low temperature in International Falls for the first week of the month are
Arrange these values in ascending order.
-31, -29, -9, -8, 3, 4, 6
The total number of observations is 7, which is an odd number. So median of the sample is
The 4th term of the sample observations is -8, therefore the median of low temperature in International Falls for the first week of the month is -8.
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Lets check with every option
(a) [-4,-3]
We plug in -4 for x and -3 for x
f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.
(b) [-3,-2]
We plug in -3 for x and -2 for x
f(-2) is negative and f(-3) is negative. there is no value at x=c on the interval [-3,-2] where f(c)=0.
(c) [-2,-1]
We plug in -2 for x and -1 for x
f(-2) is negative and f(-1) is positive. there is some value at x=c on the interval [-2,-1] where f(c)=0. so there exists atleast one zero on this interval.
(d) [-1,0]
We plug in -1 for x and 0 for x
f(-1) is positive and f(0) is negative. there is some value at x=c on the interval [-1,0] where f(c)=0. so there exists atleast one zero on this interval.
(e) [0,1]
We plug in 0 for x and 1 for x
f(0) is negative and f(1) is negative. there is no value at x=c on the interval [0,1] where f(c)=0.
(f) [1,2]
We plug in 1 for x and 2 for x
f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.
so answers are (a) [-4,-3], (c) [-2,-1], (d) [-1,0], (f) [1,2]