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Lana71 [14]
2 years ago
5

Tyre pressure for car

Physics
2 answers:
Mashcka [7]2 years ago
5 0

Answer:

oxygen expanding unjhfyysue hjdbdhdjjhd

Sonja [21]2 years ago
3 0

Answer:

32 psi to 35 psi.

Explanation:

Normal tire pressure is usually between 32~40 psi(pounds per square inch) when they are cold. So make sure you check your tire pressure after a long stay and usually, you can do it in the early morning.

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Kim designed an experiment to show how heat can be transferred from one place to another. The steps of the experiment are shown
Radda [10]
Heat transfer by conduction, since kim is trying to show that heat travels from one end of the rod to the other. This is nothing but conduction
3 0
3 years ago
A helium-neon laser emits light of wavelength 632.8 nm and has a power output of 16 mw. how many photons are emitted per second
NemiM [27]
The power of the laser is
P=16 mW=0.016 W
by using the relationship between power, energy and time, we can find the energy delivered by the laser in 1 second:
E=Pt=(0.016 W)(1 s)=0.016 J

The frequency of the photons of this light is given by
f= \frac{c}{\lambda}= \frac{3\cdot 10^8 m/s}{632.8 \cdot 10^{-9} m} =4.74 \cdot 10^{14} Hz
and the energy of a single photon is
E_1=hf=(6.6\cdot 10^{-34} Js)(4.74 \cdot 10^{14} Hz)=3.13 \cdot 10^{-19} J

In order to find the number of photons emitted per second, we must divide the total energy emitted by the laser by the energy of a single photon, and we get:
N= \frac{E}{E_1}= \frac{0.016 J}{3.13 \cdot 10^{-19}J} =5.11 \cdot 10^{16} photons
7 0
3 years ago
Octane is an important component of gasoline. Octane will ignite at a temperature of 428°F. What is this temperature on the Cels
xxMikexx [17]
The requirement is to change the °F to °C scale. That is;

T(°C) = [T(°F) - 32]/1.8

Substituting;

T(°C) = [428 - 32]/1.8 = 396/1.8 = 220 °C.

Therefore, 428°F will be 220°C on Celsius scale.
5 0
4 years ago
A speeding car is pulling away from a police car. The police car is moving at 30 m/s. The radar gun in the police car emits an e
Gekata [30.6K]

Answer:

65.625 m/s

Explanation:

F=20\times 10^9 Hz

\Delta F=F_r-F_t=4750 Hz

c = Speed of light = 3×10⁸ m/s

Relative speed

v=\frac{\Delta F}{2F}\times c\\\Rightarrow v=\frac{4750}{2\times 20\times 10^9}\times 3\times 10^8\\\Rightarrow v=35.625\ m/s

Relative speed = 35.625 m/s

Velocity of speeder = Velocity of police car + Relative speed

⇒Velocity of speeder = 30 + 35.625 = 65.625 m/s

∴ Velocity of speeder is 65.625 m/s

6 0
4 years ago
Which option was changed in the "Waves" lab to see how it would affect wave speed?
gizmo_the_mogwai [7]

Answer:

B. how hard the string was plucked

Explanation:

4 0
4 years ago
Read 2 more answers
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