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2 years ago

14

es peso de na persona en la tiera es de 600N. determinar a)la masa de la persona b) el peso de la persona en la luna desde ,dond

e la aceleracion es 1.6 m/s

2 answers:

Oduvanchick [21]2 years ago

8 0

Answer:

jn

Explanation:

Viktor [21]2 years ago

8 0

What are you trying to say ?

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Technician A says that a tire will increase or decrease approximately 1 psi for each 10°F change of temperature. Technician B sa

bearhunter [10]

Answer:

Technician A

Explanation:

It is seen that a tire pressure will increase or decrease 1 psi for each $10^{\circ} F$ change in temperature.

For Technician B vehicle pressure should not be adjusted after tire has been warmed as the warm air may increase the pressure but it will be auto adjusted as the temperature falls to normal .

8 0

3 years ago

How does a arrow represent displacement

Lera25 [3.4K]

Answer:

An arrow represents displacement. Because it's a vector quantity.

Vector quantity= Direction+Magnitude

When an arrow is put above a unit like

acceleration
displacement

it means that it's a vector quantity.

Hope this helps ;) ❤❤❤

4 0

3 years ago

Consider a spring mass system (mass m1, spring constant k) with period T1. Now consider a spring mass system with the same sprin

tatuchka [14]

Answer:

Assuming that both mass here move horizontally on a frictionless surface, and that this spring follows Hooke's Law, then the mass of $m_2$ would be four times that of $m_1$ .

Explanation:

In general, if the mass in a spring-mass system moves horizontally on a frictionless surface, and that the spring follows Hooke's Law, then

$\displaystyle \frac{m_2}{m_1} = \left(\frac{T_2}{T_1}\right)^2$ .

Here's how this statement can be concluded from the equations for a simple harmonic motion (SHM.)

In an SHM, if the period is $T$ , then the angular velocity of the SHM would be

$\displaystyle \omega = \frac{2\pi}{T}$ .

Assume that the mass starts with a zero displacement and a positive velocity. If $A$ represent the amplitude of the SHM, then the displacement of the mass at time $t$ would be:

$\mathbf{x}(t) = A\sin(\omega\cdot t)$ .

The velocity of the mass at time $t$ would be:

$\mathbf{v}(t) = A\,\omega \, \cos(\omega\, t)$ .

The acceleration of the mass at time $t$ would be:

$\mathbf{a}(t) = -A\,\omega^2\, \sin(\omega \, t)$ .

Let $m$ represent the size of the mass attached to the spring. By Newton's Second Law, the net force on the mass at time $t$ would be:

$\mathbf{F}(t) = m\, \mathbf{a}(t) = -m\, A\, \omega^2 \, \cos(\omega\cdot t)$ ,

Since it is assumed that the mass here moves on a horizontal frictionless surface, only the spring could supply the net force on the mass. Therefore, the force that the spring exerts on the mass will be equal to the net force on the mass. If the spring satisfies Hooke's Law, then the spring constant $k$ will be equal to:

$\begin{aligned} k &= -\frac{\mathbf{F}(t)}{\mathbf{x}(t)} \\ &= \frac{m\, A\, \omega^2\, \cos(\omega\cdot t)}{A \cos(\omega \cdot t)} \\ &= m \, \omega^2\end{aligned}$ .

Since $\displaystyle \omega = \frac{2\pi}{T}$ , it can be concluded that:

$\begin{aligned} k &= m \, \omega^2 = m \left(\frac{2\pi}{T}\right)^2\end{aligned}$ .

For the first mass $m_1$ , if the time period is $T_1$ , then the spring constant would be:

$\displaystyle k = m_1\, \left(\frac{2\pi}{T_1}\right)^2$ .

Similarly, for the second mass $m_2$ , if the time period is $T_2$ , then the spring constant would be:

$\displaystyle k = m_2\, \left(\frac{2\pi}{T_2}\right)^2$ .

Since the two springs are the same, the two spring constants should be equal to each other. That is:

$\displaystyle m_1\, \left(\frac{2\pi}{T_1}\right)^2 = k = m_2\, \left(\frac{2\pi}{T_2}\right)^2$ .

Simplify to obtain:

$\displaystyle \frac{m_2}{m_1} = \left(\frac{T_2}{T_1}\right)^2$ .

6 0

3 years ago

A girl and a boy pull in opposite directions on strings attached to each end of a spring balance. Each child exerts a force of 2

BabaBlast [244]

Answer:

yo they deleted my answer. The answer is 0N

Explanation:

so when two forces pull on an object from opposite sides with the same force (in this case its 20N), then the object is in equilibrium at 0N.

So its clear that there is one person on the the opposite side.

SOOO generally<u>: (left or down) would be considered </u><u>negative</u><u> in an equation. And the other person (right or up) would be considered </u><u>positive</u><u>.</u> So if both forces are the same numbers on opposite sides then the answer is 0 (if you add both of them).

<em>0 is the number of equilibrium.</em>

OK, so the equation would be -20N + 20N and then badda bing badda boom viola, the answer: 0N

thanks for coming to my TED talk. I hope they don't delete this answer.

5 0

3 years ago

Calculate the ph of the solution that results following addition of 24 ml of 1.0 mnaoh to 60 ml of 1.0 mnh4cl.

Lostsunrise [7]

The pH of the solution is 0.37.

<h3>What is the pH of the solution?</h3>

We can write the equation of the reaction as;

$NH4Cl (aq) + NaOH (aq) ------- > NH3 (aq) + H2O (l) + NaCl (aq)$

Number of moles of $NaOH$ = 24/1000 * 1 = 0.024 moles

Number of moles of $NH4Cl$ = 60/1000 * 1 = 0.060 moles

Given that the reaction is 1:1, the limiting reactant is NaOH

Number of moles of NH4Cl left over = 0.060 - 0.024 = 0.036 moles

Concentration of left over NH4Cl = 0.036 moles/(24 + 60)/1000

= 0.43 moles

pH = -log(0.43)

pH = 0.37

Learn more about pH:brainly.com/question/15289741

#SPJ1

4 0

1 year ago