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3 years ago

You witness two of your class mates yelling at each other in a heated argument. this is an example of

Physics

2 answers:

AVprozaik [17]3 years ago

7 0

Answer:

Because they were both yelling at each other.

Yuliya22 [10]3 years ago

7 0

Answer: it A

Explanation:

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A loudspeaker, mounted on a tall pole, is engineered to emit 75% of its sound energy into the forward hemisphere, 25% toward the

Naily [24]

Answer:

"0.049 W" is the correct answer.

Explanation:

According to the given question,

$r = \sqrt{(3.5)^2+(2.5)^2}$

$=\sqrt{8.5}$

$SL=85$

As we know,

⇒ $SL=10 \ log(\frac{I}{I_o} )$

$85=10 \ log(\frac{I}{10^{-12}} )$

$I=3.162\times 1^{-4} \ W/m^2$

Now,

⇒ $P_{front} = I(2\pi r^2)$

$=(3.162\times 10^{-4})(2\pi\times 18.5)$

$=0.0368 \ W$

$=0.75 \ P$

or,

$=0.049 \ W$

7 0

3 years ago

A wildlife researcher is tracking a flock of geese. the geese fly 3.5 km due west, then turn toward the north by 40 ∘ and fly an

kaheart [24]

To solve this problem, we can use the cosine formula for calculating the length of the displacement:

c^2 = a^2 + b^2 – 2 a b cos θ

where c is the displacement, a = 3.5 km, b = 4.5 km, and θ is the angle inside the triangle

Since the geeze turned 40° from west to north, so the angle inside the triangle must be:

θ = 180 – 40 = 140°

c^2 = 3.5^2 + 4.5^2 – 2 (3.5) (4.5) cos 140

c^2 = 56.63

c = 7.53 km

<span>So the magnitude of the displacement is 7.53 km</span>

4 0

3 years ago

Read 2 more answers

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at

natka813 [3]

First you will want to sketch out both of the situations. It should be two sketches, one for the flagpole and one for the building.

To solve this, you will want to create a proportion.

Flagpole height/flagpole shadow=building height/building shadow

Therefore, it should look like this:
50/30= 300/x

Solve for x:
50x=9,000
X= 180 feet

YOUR ANSWER IS C.

7 0

3 years ago

A solid must be given

alexdok [17]

I- what....? Lolllll

8 0

4 years ago

Two planets X and Y travel counterclockwise in circular orbits about a star, as seen in the figure.

sergeinik [125]

Planet Y has rotated by 135.5° through during this time.

To find the answer, we need to know about the relation between angle and radius of orbit.

<h3>What's the expression of angle in terms of radius?</h3>

Angle= arc/radius
As arc = orbital velocity × time,

angle= (orbital velocity × time)/radius

Orbital velocity= √(GM/radius), G= gravitational constant and M = mass of sun
So, angle = (√(GM)× time)/radius^3/2

<h3>What's is the angle rotated by planet Y after 5 years, if ratio of the radius of orbit of planet X and Y is 4:3 and planet X is rotated by 88°?</h3>

Let Ф₁= angle rotated by planet Y, Ф₂= angle rotated by planet X
As time = 5 years ( a constant)
Ф₁/Ф₂= (radius of planet X / radius of planet Y)^(3/2)
Ф₁= (radius of planet X / radius of planet Y)^(3/2) × Ф₂

= (4/3)^(3/2) × 88°

= 135.5°

Thus, we can conclude that Planet Y has rotated by 135.5° through during this time.

Learn more about the orbital velocity here:

brainly.com/question/22247460

#SPJ1

8 0

2 years ago