Answer:
The painting is 42.13 feet above the platform
Step-by-step explanation:
Refer the attached figure .
A particular painting forming an angle of 50 degrees with a camera platform .
∠ABC = 50°
We are also given that the light is 55 feet from the wall where the painting hangs
i.e. AB = 55 feet.
Now we are required to find how high above the platform is the painting. i.e. AC
So, we will use trigonometric ratio :
Thus the painting is 42.13 feet above the platform
So we see the pythagorean theorem
a^2+b^2=c^2
diagonal=c
width=a or b, pick one
width=a
legnth=b
width is 5 times more than 2 times legnth of garden
w=5(2legnth)
this doesn't make sense since the legnth is normally longer than the width, but we'll stick with that
w=5(2l)
w=10l
a=10b
(10b)^2+b^2=90^2
100b^2+b^2=8100
101b^2=8100
divide by 101
b^2=80.198 aprox 80.2
square root
8.95533
legnth of garden =8.96
to find width subsitue
w=10l
w=89.56
legnth=8.96
width=89.56
Yes, a quadratic model does exist and its equation is f(x)=4x^2
Find the soluiton
2x+2y=16
3x-y=4
x+y=8
<u>3x-y=4+</u>
4x=12
x=3
3(3)-y=4
9-y=4
y=5
(3,5)
test them to see if get true statment
obviously the first equatons of 1,2,4 work
1 doesn't work
2, works
4. doesn't work
2 is the same as the first except both euations are just doubled
answer is 2
You got this bro why do u need our help for
