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2 years ago

Please help solve this equation?

Mathematics

1 answer:

finlep [7]2 years ago

5 0

${ \red{ \bold{cos \: y \: }}}$

Step-by-step explanation:

${ \green{ \tt{ \frac{1 \: + \: \cos \: y \: }{1 \: + \: \sec \: y \: }}}} \: → {eq}^{n} (1)$

But, as you know that

${ \blue{ \tt{sec \: y \:}}} = { \green{ \tt{\frac{1}{ \ \cos \: y }}}}$

Then the equation (1) becomes

${ \green{ \tt{ \frac{1 \: + \: cos \: y }{1 \: + \: \frac{1}{cos \: y} }}}} \:$

Multiply Numerator and Denominator by $\frac{cos \: y}{cos \: y}$

then,

${ \green{ \tt{( \frac{cos \: y}{cos \: y})}}} \: { \green{ \tt{ \frac{1 \: + \: cos \: y}{1 \: + \: \frac{1}{cos \: y}}}}}$

$= { \green{ \tt{ \frac{cos \: y \: + \: {cos}^{2} \: y }{cos \: y \: + \: 1 }}}}$

take cos y as common, then

${ \green{ \tt{cos \: y}}} \: { \green{ \tt( \frac{1 \: + \: cos \: y}{cos \: y \: + \: 1} )}}$

Here, (1+cos y/cos y + 1) gets cancelled.

Then the remaining answer is cos y.

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Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature is 45 degrees at midnig

Paraphin [41]

Answer:

D = 9sin(2π(t + a)/24) + 45

Step-by-step explanation:

Let's find the average temperature;

(54 + 36)/2 = 45°

Amplitude = 54 - 45 = 9

From the wave equation, we can write the temperature as;

D = 9sin(2π(t + a)/24) + 45

Where;

D is the temperature

t is the time in hours after midnight

a is a "phase" that is used to set the time at which temperature(D) occurs

5 0

3 years ago

If y=27 when x= 8 find y when x =11

Rina8888 [55]

Answer:

37 1/8

Step-by-step explanation:

The problem probably assumes direct variation

y=kx

IF so, then plug in the values and solve for k

27=k(8)

k = 27/8

y= (27/8)x. Now let x = 11

y = (27/8)11 = 27(11)/8 = 37.125 = 37 1/8

y = 37 1/8

the problem is making some assumption about the relation between x and y. The simplest assumption that's likely is direct variation, that x and y are linearly related. The graph is a straight line through the origin with slope = 27/8

6 0

3 years ago

Need understanding how to do this

kkurt [141]

Answer:

102 + (3x +2) = 180 . . . . equation to solve
x = 25 1/3 . . . . . . . . . . . . value of x

Step-by-step explanation:

It can be helpful to draw a diagram of a parallelogram ABCD and identify the angles in the problem statement. You will find they are adjacent angles.

Adjacent angles in a parallelogram are supplementary, so the sum of the given angle measures will be 180°.

102 + (3x +2) = 180 . . . equation used to solve for x

3x = 76 . . . . . . . . . . . . . subtract 104

x = 76/3 . . . . . . . . . . . . divide by 3

x = 25 1/3 . . . the value of x

7 0

3 years ago

Lin rode a bike 20 miles in 150 minutes. If she rode at a constant speed, how far did she ride in 15 minutes? How long did it ta

coldgirl [10]

Hey there! :)

Answer:

First part: 2 miles.

Second part: 45 minutes

Third part: 8 mph.

Step-by-step explanation:

We can divide this question into 3 parts.

Begin by solving for the distance traveled after 15 minutes by creating a ratio:

$\frac{20 mi}{150min} = \frac{x}{15 min}$

Cross multiply:

20 · 15 = 150 · x

300 = 150x

300/150 = 150x/150

x = 2 miles.

2nd part: How long it took her to ride 6 miles.

Set up another ratio similar to the one used before:

$\frac{20 mi}{150min} = \frac{6mi}{x min}$

Cross multiply:

20 · x = 6 · 150

20x = 900

20x/20 = 900/20

x = 45 minutes.

3rd part:

For this part, we will need to convert from minutes to hours.

$\frac{20 mi}{150 min}* \frac{60 min}{1 hr} = \frac{1200mi}{150hr} = 8 mi/h$

Therefore, her speed is 8 mph.

5 0

3 years ago

Help Help Help Help Help Help

TEA [102]

Answer:

Its bus 1 hope it helps goodluck

4 0

3 years ago