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Daniel [21]
3 years ago
8

5. The differential equation y 00 − xy = 0 is called Airy’s equation, and is used in physics to model the refraction of light. (

a) Assume a power series solution, and find the recurrence relation of the coefficients. [Hint: When shifting the indices, one way is to let m = n − 3, then factor out x n+1 and find an+3 in terms of an. Alternatively, you can find an+2 in terms of an−1.] (b) Show that a2 = 0. [Hint: the two series for y 00 and xy don’t “start” at the same power of x, but for any solution, each term must be zero. (Why?)] (c) Find the particular solution when y(0) = 1, y 0 (0) = 0, as well as the particular solution when y(0) = 0, y 0 (0) = 1.

Mathematics
1 answer:
storchak [24]3 years ago
4 0

Not sure why, but I wasn't able to post my solution as text, so I've written it elsewhere and am posting screenshots of it here.

In the fifth attachment, the first solution is shown above the second one.

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Solve the equation 14y+82=6x-20 for x if y is 25
Leni [432]

Answer:

x= 226/3 or 75.33333333333333333333333333333

Step-by-step explanation:

14y+82=6x-20

y=25

Sub y=25 into 14y+82=6x-20

14y+82=6x-20

14(25)+82=6x-20

Calculate as follows:

14(25)+82=6x-20

350+82=6x-20

432=6x-20

Add twenty to both sides:

432+20=6x-20+20

452=6x-0

452=6x

Divide both sides by 6

452=6x

452/6=6x/6

452/6=x

x= 226/3 or 75.33333333333333333333333333333

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Answer:

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Step-by-step explanation:

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2 years ago
convert the following logarithmic equation to the equivalent exponential equation. Use the caret (^) to enter exponents. y=ln x
GarryVolchara [31]
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3 years ago
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




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3 years ago
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ExtremeBDS [4]

Answer:

x=\frac{27}{2}\:\text{or}\:13.5

Step-by-step explanation:

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5 0
2 years ago
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