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katovenus [111]
3 years ago
5

Find the domain of the following function.

7D%20" id="TexFormula1" title="f(x) = \sqrt[7]{x - 9} " alt="f(x) = \sqrt[7]{x - 9} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0
Domain<span>: The set of all possible input values (commonly the "x" variable) It is the set of all real numbers for which a function is mathematically defined.  

</span>f(x) =  \sqrt[1]{x-9} 
<span>
The function has noun defined points nor domain constraints. Therefore, the domain is 

</span>- \infty} \ \textless \  x \ \textless \  \infty}<span>
</span>
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X-30% is 12. What is X?
skad [1K]
If i'm not wrong,i think the answer is:

30%=0.3
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5 0
3 years ago
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For which equation is x=5 a solution? Help me please ty :)
VladimirAG [237]

Answer:

B)3x=15

Step-by-step explanation:

3x=15

x=15/3

x=5 (proven)

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I NEED THIS ASAP please. can someone please answer this question i put the picture its on Simplify Expressions im giving 15 poin
kakasveta [241]

Answer:

in step 4

Step-by-step explanation:

we have

0.5(-12c+6)-3(c+4)+10(c-5)\\\\step1=-12c(0.5)+6(0.5)-3(c+4)+10(c-5)\\\\=-6c+3-3(c+4)+10(c-5)\\\\

so step 1 is correct

step 2

-6c+3-3(c+4)+10(c-5)\\\\=-6c+3+c(-3)+4(-3)+10(c-5)\\\\=-6c+3-3c-12+10(c-5)

so step 2 is correct

step 3

-6c+3-3c-12+10(c-5)\\\\=-6c+3-3c-12+c(10)-5(10)\\\\=-6c+3-3c-12+10c-50

so step 3 is correct

step 4

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5 0
3 years ago
Seven-ninths of the pencils in a box are yellow. Three-tenths of the yellow pencils are sharpened. What fraction represents the
jek_recluse [69]

Answer:

7/30

Step-by-step explanation:

We are given that Seven-ninths (7/9) of the pencils in a box are yellow and three-tenths (3/10) of the yellow pencils are sharpened.

To find the fraction that represents sharpened yellow pencils, we find the product of the the fraction of yellow pencils and the fraction of yellow pencils that are sharpened.

That is:

=> (7 / 9) * (3 / 10)

=(7 * 3) / (9 * 10)

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= 7 / 30

7/30 represents the fraction of sharpened yellow pencils.

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3 years ago
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