The greatest whole humber like that is 987654321
Let the width be x m, then the length is 2x-7 m.
If the length is decreased by 1m, then new length is 2x-7-1=2x-8 m.
If the width is decreased by 4 m, then new width is x-4 m.
Find the perimeter of new recangle:
![P_{new}=2x-8+x-4+2x-8+x-4=6x-24.](https://tex.z-dn.net/?f=P_%7Bnew%7D%3D2x-8%2Bx-4%2B2x-8%2Bx-4%3D6x-24.)
The perimeter of new rectangle is 66 m, then
![6x-24=66,\\\\6x=66+24,\\\\6x=90,\\\\x=15.](https://tex.z-dn.net/?f=6x-24%3D66%2C%5C%5C%5C%5C6x%3D66%2B24%2C%5C%5C%5C%5C6x%3D90%2C%5C%5C%5C%5Cx%3D15.)
Therefore, old width was 15 metres and old length was 2·15-7=23 metres.
Answer: original width: 15 metres, original length: 23 metres
Answer:
A.) $3,159.30
Step-by-step explanation:
We have been given that a boat costs $16,600 and decreases in value by 14% per year.
We will use exponential decay formula to solve our given problem.
, where,
y = Final amount,
A = Initial value,
r = Decay rate in decimal form.
![14\%=\frac{14}{100}=0.14](https://tex.z-dn.net/?f=14%5C%25%3D%5Cfrac%7B14%7D%7B100%7D%3D0.14)
![y=\$16,600\cdot (1-0.14)^11](https://tex.z-dn.net/?f=y%3D%5C%2416%2C600%5Ccdot%20%281-0.14%29%5E11)
![y=\$16,600\cdot (0.86)^11](https://tex.z-dn.net/?f=y%3D%5C%2416%2C600%5Ccdot%20%280.86%29%5E11)
![y=\$16,600\cdot 0.1903193578437064](https://tex.z-dn.net/?f=y%3D%5C%2416%2C600%5Ccdot%200.1903193578437064)
![y=\$3159.3013402055](https://tex.z-dn.net/?f=y%3D%5C%243159.3013402055)
![y\approx \$3159.30](https://tex.z-dn.net/?f=y%5Capprox%20%5C%243159.30)
Therefore, the value of boat after 11 years would be $3159.30 and option A is the correct choice.
Answer:
20/5=number in each group. It can also be S/5
Step-by-step explanation: