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Romashka-Z-Leto [24]
2 years ago
12

2. In the diagram below, set I represents rational numbers, set II represents integers, and set III represents whole numbers. Sh

ade the values that belong in set II. 05 -0.5 13.2 24 0 - 5 10 2 -9.0 35 ] 1 -4.91 I II III​
Mathematics
1 answer:
MrRa [10]2 years ago
5 0

The information about the rational numbers and integers shows that the correct option is C.

<h3>How to explain the information?</h3>

It should be noted that rational numbers are numbers where we can write as a fraction of two integers. Any rational number is in the form a/b where a,b are integers and b is nonzero.

Terminating decimals can be written as a rational number. Something like 3.1 is equivalent to 31/10.

Of the four answer choices, only choice C is correct.

Choice A has the value '3' as a rational number, but it doesn't have it in the set of integers as well. So that's why choice A is incorrect.

Choice B has -3.4 in the set of integers, which is not correct. Integers do not have any decimal portion. The same applies to choice D also. We can rule choices B and D out.

Therefore, the correct option is C.

Learn more about integers on:

brainly.com/question/17695139

#SPJ1

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Can someone pleaseeee help if you’re correct I’ll give u brainlist
nikklg [1K]

Answer:

C

Step-by-step explanation:

since it is a line segment it is only that portion of a line, so its s, t and all in between

8 0
3 years ago
I GIVE THANKS AND 5 STARS!!
goldenfox [79]
The number of permutations is 5!.
5! = 5 x 4 x 3 x 2 x 1 = 120
4 0
4 years ago
How to get the variable for ×+13=25
Blababa [14]
You subtract 13 from both sides of the = sign so ×=12
4 0
3 years ago
Read 2 more answers
10<br> Using the quadratic formula to solve x2 = 5 – X, what are the values of x?
loris [4]

x^2 = 5 - x

x^2 + x - 5 = 0

-1 +/-\frac{ \sqrt{ {1}^{2} - 4(1 \times  - 5) } }{2}

x = (1 + √21) / 2

x = (1 - √21) / 2

6 0
3 years ago
[18].Simplify (TTE): x(2x+y+5) - 2(x²+xy+5) + y(x + y) <br>​
Dovator [93]

Answer:

x(2x+y+5) - 2(x\²+xy+5) + y(x + y) = 5x -10  + y\²

Step-by-step explanation:

Given

x(2x+y+5) - 2(x\²+xy+5) + y(x + y)

Required

Simplify

We have:

x(2x+y+5) - 2(x\²+xy+5) + y(x + y)

Open brackets

x(2x+y+5) - 2(x\²+xy+5) + y(x + y) = 2x\²+xy+5x - 2x\²-2xy-10 + xy + y\²

Collect like terms

x(2x+y+5) - 2(x\²+xy+5) + y(x + y) = 2x\²- 2x\²+xy-2xy+ xy+5x -10  + y\²

x(2x+y+5) - 2(x\²+xy+5) + y(x + y) = 5x -10  + y\²

4 0
3 years ago
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