All categories

3 years ago

TheSolution to the equation is ??

Mathematics

1 answer:

spayn [35]3 years ago

5 0

Answer:

X = 1

Step-by-step explanation:

2x^2 + x - 1 = 2

2x^2 + x - 3 = 0

2x^2 + 3x -2x - 3 = 0

x(2x+3) -1 ( 2x+3) = 0

(x-1) (2x+3) = 0

x-1=0

x=1

2x+3=0

2x=-3

x=-3/2.

You might be interested in

Review 2019-2020 7 1 of 25

Lerok [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

8) Factor each sum or difference of cubes completely.<br> a. 8x3 + 27

ASHA 777 [7]

Answer:

$\large\boxed{(2x+3)(4x^2-6x+9)}$

Step-by-step explanation:

$8=2^3\\\\8x^3=2^3x^3=(2x)^3\\\\27=3^3\\\\8x^3+27=(2x)^3+3^3\qquad\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(2x+3)\bigg((2x)^2-(2x)(3)+3^2\bigg)=(2x+3)(4x^2-6x+9)$

4 0

3 years ago

What is the value of x? Round to the nearest tenth.

kotykmax [81]

Answer:

27.5

Step-by-step explanation:

first you find what 30x30 is as A squared plus B squared is equal to C squared. your A is 12 and your C is 30.

so!

30x30 is 900

12x12 is 144

subtract 144 from 900 and you get 756. once you find the square root you get 27.49. then round up to 27.5

5 0

3 years ago

Read 2 more answers

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

6 0

3 years ago

State the y-coordinate of the y-intercept for the function below.

Molodets [167]

When y intercpets, x = 0
so here,

ƒ(x)=x^3-x^2-x+1
ƒ(x)=(0)^3-(0)^2-0+1
ƒ(x)= +1

3 0

2 years ago

Read 2 more answers