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wolverine [178]
3 years ago
8

TheSolution to the equation is ??

Mathematics
1 answer:
spayn [35]3 years ago
5 0

Answer:

X = 1

Step-by-step explanation:

2x^2 + x - 1 = 2

2x^2 + x - 3 = 0

2x^2 + 3x -2x - 3 = 0

x(2x+3) -1 ( 2x+3) = 0

(x-1) (2x+3) = 0

x-1=0

x=1

2x+3=0

2x=-3

x=-3/2.

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Let u= <4,3>. Find the unit vector in the direction of u, and write your answer in component form.
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Take the vector u = <ux, uy> = <4, 3>.

Find the magnitude of u:

||u|| = sqrt[ (ux)^2 + (uy)^2]

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To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is

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I hope this helps. =)
3 0
3 years ago
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Which means.. the equation is
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