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Y_Kistochka [10]
2 years ago
15

A vibrating guitar string makes very little sound if it is not mounted on the guitar body. Why does the sound have greater inten

sity if the string is attached to the guitar body? (a) The string vibrates with more energy. (b) The energy leaves the guitar at a greater rate. (c) The sound power is spread over a larger area at the listener's position.(d) The sound power is concentrated over a smaller area at the listener's position. (e) The speed of sound is higher in the material of the guitar body. (f) None of these answers is correct.
Physics
1 answer:
puteri [66]2 years ago
6 0

A vibrating guitar string makes very little sound if it is not mounted on the guitar body. The string vibrates with more energy. So, the sound have greater intensity if the string is attached to the guitar body.

When strumming, excessive force might cause the strings to vibrate excessively up and down (as opposed to side to side), which increases the likelihood of buzzing. The neck is probably back bowed if all or the majority of the strings buzz when played openly.

In order to accomplish work and to produce heat and light, energy must be transferred to a body or to a physical system. Energy is the quantitative attribute that does this. Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or destroyed.

A guitar string is a string that is strung across a wooden instrument or an instrument with magnetic or piezoelectric pickups. These strings are commonly made of gut, nylon, or steel. The string's function is to vibrate and generate a certain musical note.

Learn more about guitar string here:

brainly.com/question/14417581

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A substance with a density of 16.8 g/ml has a mass of 3.2 g. what is its volume?
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We know that d=m/v where d is density, m is mass and v is volume. Lets transform formula to get v in times of d and m
d= \frac{m}{V}  /*V \\ V*d=m /:d \\ V= \frac{m}{d}
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4 0
3 years ago
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A hot-air balloon is ascending at the rate of 10 m/s and is 74 m above the ground when a package is dropped over the side. (a) H
Reika [66]

Answer:

The answer to your question is:

a)  t1 = 2.99 s ≈ 3 s

b)  vf = 39.43 m/s

Explanation:

Data

vo = 10 m/s

h = 74 m

g = 9.81 m/s

t = ?   time to reach the ground

vf = ?   final speed

a)    h = vot + (1/2)gt²

     74 = 10t + (1/2)9.81t²

     4.9t² + 10t -74 = 0                  solve by using quadratic formula

   

   t = (-b ± √ (b² -4ac) / 2a

   t = (-10 ± √ (10² -4(4.9(-74) / 2(4.9)

   t = (-10 ± √ 1550.4 ) / 9.81

  t1 = (-10 + √ 1550.4 ) / 9.81               t2 = (-10 - √ 1550.4 ) / 9.81

  t1 = (-10 ± 39.38 ) / 9.81                    t2 = (-10 - 39.38) / 9.81

   t1 = 2.99 s ≈ 3 s                               t2 = is negative then is wrong there are

                                                                   no negative times.

b) Formula vf = vo + gt

                  vf = 10 + (9.81)(3)

                  vf = 10 + 29.43

                  vf = 39.43 m/s

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3 years ago
Two copper spheres are currently 1.2 meters apart.One sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4
Fofino [41]

Two copper spheres are currently 1.2 meters apart. One sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.

<h3>What is Coulomb's law?</h3>

Coulomb's law can be expressed as that the electrical force between two charged bodies is directly proportional to the product of the quantity of charge on the bodies and inversely proportional to the square of the separation distance between the two bodies.

As given in the problem two copper spheres are currently 1.2 meters apart.One sphere has a charge of +2.2•10-4 C and the other has a charge of - 8.9•10-4 C.

As per coulomb's law, opposite charges attract each other.

Thus, If one sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.

Learn more about Coulomb's law here ;

brainly.com/question/506926

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