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kondaur [170]
3 years ago
9

The engineer determines that the machine increased at a constant rate the disk’s angular speed from 100 rad/s to 300 rad/s over

a time of 5 seconds. What was the angular displacement of the disk during those 5 seconds?
Physics
1 answer:
aleksklad [387]3 years ago
5 0

The disk's average angular speed during those 5 seconds was

(1/2) (100 + 300) rad/s = 200 rad/sec

Spinning for 5 sec at an average angular speed of 200 rad/s, the disk turned

(200 rad/s) x (5 s)  =  <em>1,000 radians</em>

(That's 500/pi revolutions = roughly 159.2 revolutions.)

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A capacitor is connected across an ac source. Suppose the frequency of the source is doubled. What happens to the capacitive rea
fgiga [73]

The capacitive reactance is reduced by a factor of 2.

<h3>Calculation:</h3>

We know the capacitive reactance is given as,

Xc = \frac{1}{2\pi fC}

where,

Xc\\ = capacitive reactance

f = frequency

C = capacitance

It is given that frequency is doubled, i.e.,

f' = 2f

To find,

Xc =?

Xc' = \frac{1}{2\pi f'C}

      = \frac{1}{2\pi 2f C}

      = \frac{1}{2} (\frac{1}{2\pi fC} )\\

Xc' = \frac{1}{2} Xc

Therefore, the capacitive reactance is reduced by a factor of 2.

I understand the question you are looking for is this:

A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?

  1. The capacitive reactance is doubled.
  2. The capacitive reactance is traduced by a factor of 4.
  3. The capacitive reactance remains constant.
  4. The capacitive reactance is quadrupled.
  5. The capacitive reactance is reduced by a factor of 2.

Learn more about capacitive reactance here:

brainly.com/question/23427243

#SPJ4

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Explanation:

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