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kondaur [170]
3 years ago
9

The engineer determines that the machine increased at a constant rate the disk’s angular speed from 100 rad/s to 300 rad/s over

a time of 5 seconds. What was the angular displacement of the disk during those 5 seconds?
Physics
1 answer:
aleksklad [387]3 years ago
5 0

The disk's average angular speed during those 5 seconds was

(1/2) (100 + 300) rad/s = 200 rad/sec

Spinning for 5 sec at an average angular speed of 200 rad/s, the disk turned

(200 rad/s) x (5 s)  =  <em>1,000 radians</em>

(That's 500/pi revolutions = roughly 159.2 revolutions.)

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Answer:

\phi = 0.66 rad

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Explanation:

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If we take the derivative of x with respect to t from (1), we can find the velocity equation of this motion:

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Dividing 4 by 3 we have:

\frac{v(0)}{x(0)}=-\omega tan(\phi)

\phi = tan^{-1}(\frac{-v(0)}{\omega x(0)})

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Now, using (3) we can find the amplitude.

A = \frac{x(0)}{cos(\phi)} = 5.06 cm

I hope it helps!                            

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