In an AP, the 8th term is equal to the sum of the first 8
terms. Show that the 4th term is 0
1 answer:
Answer:
let the first term of an A.P. is 'a' and common difference 'd'
∴ 8th term = sum of the first 8 terms
a8 = S
a + 7d = 8/2(2a + (8 - 1)d)
a + 7d = 8/2(2a + 7d)
2a + 14d = 16a + 56d
16a + 56d - (2a + 14d) = 0
14a + 52d = 0
divide eq. by 14 we get ,
a + 3d = 0
and a + 3d = a4 = 0
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