Question

(02.02)

Answer 1

Let

L--------> the length of the rectangle

y------> the width of the rectangle

x------> the perimeter of the rectangle

we know that

The perimeter of the rectangle is equal to

In this problem we have

For a width  

Find the value of the perimeter

so

therefore

the answer is the option A

No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y. .