1) in first place you need to Know what kind of figure is it, in order to find solve the problem, as you can see it is a parallelogram, and the condition for this geometric figure the opposites are equal ,
2) if you have a non -rectangular parallelogram and draw a diagonal from A to C, you obtain two equal triangles, for this reason the line AC IS CALLED DIAGONAL, and divide the parallelogram
3) in first place to determine that the angles are congruents for two triangles the Diagonal is comun for both, and the vertex ∡CAB IS THE SAME ∡ACD
4) If the diagonal AB AND CD are equal , AD AND BC are equal too, then the triangles are congruent
5) segment AB Parallel to CD THEY HAVE THE SAME SLOPE AND MAGNITUDE
360 degrees. x+y+z = 360°
The costs of each game was A. $3.50
$21 - $7\4 = $3.50
![\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5Be%5E%7B2y%7D-y%5Ccos%20xy%5Cright%5D%3D2e%5E%7B2y%7D-%5Ccos%20xy%2Bxy%5Csin%20xy)
![\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20x%7D%5Cleft%5B2xe%5E%7B2y%7D-y%5Ccos%20xy%2B2y%5Cright%5D%3D2e%5E%7B2y%7D%2By%5Csin%20xy)
The partial derivatives are not equal, so the equation is not exact.
