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2 years ago

-4,-8, -16,... what is the 7th term sequence

Mathematics

1 answer:

AVprozaik [17]2 years ago

8 0

If the sequence is -4,-8,-16,.. then the seventh term be -256.

Given a sequence be -4,-8,-16,...

We are required to find the seventh term of the sequence.

If we carefully observe the sequence then we will find that the sequence is a geometric progression.

Geometric progression is a sequence which has a common ratio between all the terms.

Ratio of 2nd and 3rd term=-8/-4=2

Ratio of 3rd and 2nd term=-16/-8=2

Because the ratio is equal, so the sequence will be called a geometric progression.

Nth term of G.P=a $r^{n-1}$

7th term=-4* $(2)^{7-1}$

=-4*64

=-256

Hence if the sequence is -4,-8,-16,.. then the seventh term be -256.

Learn more about geometric progression at brainly.com/question/24643676

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Answer:

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There is no equation in what you typed on the third lie so it cannot be solved (equal sign is missing)

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Step-by-step explanation:

For all cases the goal is to isolate the unknown (represented by a letter) on one side of the equal sign by using mathematical operations simultaneously on both sides.

In the first equation, to isolate z we need to subtract 4 from both sides:

$-3=z+4\\-3-4=z+4-4\\-3-4=z\\z=-7$

In the second equation: in order to isolate x we need to get rid of the factor 4 that is multiplying x, therefore we use the division by 4 on both sides:

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The third expression you wrote doesn't contain an equal sign and therefore it s not an equation (cannot be solved)

In the last equation, in order to isolate x we need to divide both sides by 7 and also to multiply both sides by 33:

$-4=\frac{7}{33} x\\\frac{-4*33}{7} =\frac{7*33}{33*7} x\\\frac{-132}{7} = x\\x=-\frac{132}{7}$

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