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14+14=28 0r 7x4=28or14x2=28 or28-0=28
1.) Parallel lines has equal slopes. Line y = -4 has a slope of 0.
Required equation is y - y1 = 0
y - 5 = 0
y = 5
2.) Required equation is y - y1 = m(x - x1); where m is the slope and (x1, y1) = (-3, 4)
y - 4 = -2/3(x - (-3))
y - 4 = -2/3(x + 3)
y - 4 = -2/3 x - 2
y = -2/3 x - 2 + 4
y = -2/3 x + 2
What do you need help with?
By "y = −9x2 − 2x" I assume you meant <span>y = −9x^2 − 2x (the "^" symbol represents exponentiation).
Let's find the first derivative of y with respect to x: dy/dx = -18x - 2. This is equivalent to the slope of the tangent line to the (parabolic) curve. Now let this derivative (slope) = 0 and solve for the critical value: -18x - 2 = 0, or
-18x = 2. Solving for x, x = -2/18, or x = -1/9.
When x = -1/9, y = -9(-1/9)^2 - 2(-1/9). This simplifies to y = -9/9 + 2/9, or
y = -7/9.
The only point at which the tangent to the curve is horiz. is (-1/9,-7/9).</span>