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yan [13]
3 years ago
12

7, 9, 13, 4, 18, 3, 9, 10, 15, 8, 2, 6, 9 What is the range, q1, q3 and iqr

Mathematics
1 answer:
kipiarov [429]3 years ago
7 0

Answer:

Range: 16

Q1: 5

Q3: 11.5

IQR: 6.5

Step-by-step explanation:

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gizmo_the_mogwai [7]

Answer:

The answer is:

The angle of rotation counterclockwise about the spinner's center that maps label g to label B is 180° .

Step-by-step explanation:

The angle of rotation counterclockwise about the spinner's center that maps label g to label B is 180° .

Look at the attached picture of a spinner:

We know that the angle formed by a straight line is  equal to 180°

So, in order to map label g to label B we have to set the needle of the spinner straight. Hence the angle formed by the needle is 180° ....

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Leokris [45]

Answer:

18 red marbles

Step-by-step explanation:

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3 years ago
Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

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\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

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shepuryov [24]

Answer:

Step-by-step explanation:

First equation

x + y ≥ 10

Second equation

5.50x + 3y ≤ 45

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x = 4 and y= 6

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What is 3/6 plus 1/3
aksik [14]

Answer:

5/6

Step-by-step explanation:

3/6 + 1/3 = 3/6 + 2/6 = 5/6

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