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Blizzard [7]
2 years ago
10

The volume of Cube A is 8 cubic inches. The face of Cube B has an area of 64 square inches. Which cube has a greater side​ lengt

h?
Mathematics
1 answer:
defon2 years ago
8 0

The cube which has a greater side length according to the task content is; Cube B.

<h3>Which cube has a greater side length?</h3>

It follows from the task content that since cube A has a volume of 8 in³, it follows that its side length is;

s(A) = ³√8 = 2in.

Also, since one face of cube B has an area of 64 in², it follows that the side length is;

s = ²√64

s(B) = 8 in.

Hence, Cube B has the greater side length.

Read more on volume of a cube;

brainly.com/question/18762961

#SPJ1

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Find four consecutive even integers such that seven times the first exceeds their sum by 18.
Ganezh [65]

Answer:

10, 12, 14, 16

Step-by-step explanation:

Given: Four consecutive even integers such that seven times the first exceeds their sum by 18.

Lets assume the first number be "x".

As it is even integers

∴ Second consecutive number will be (x+2)

  Third consecutive number will be (x+4)

  Fourth consecutive number will be (x+6)

Now, as given seven times the first exceeds their sum by 18.

∴ [x+(x+2)+(x+4)+(x+6)]+18 = 7x

solving the equation to find the number.

⇒ [x+(x+2)+(x+4)+(x+6)]+18 = 7x

Opening parenthesis

x+x+2+x+4+x+6+18 = 7x

⇒ 4x+30= 7x

subtracting both side by 4x

⇒ 30= 3x

Dividing both side by 3

∴ x= 10.

Hence, subtituting the value x to find four consecutive even integers.

  First number is 10

  Second consecutive number will be (10+2) = 12

  Third consecutive number will be (10+4)= 14

  Fourth consecutive number will be (10+6) = 16

∴ Four consecutive even integers are 10,12,14,16.

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